In simple terms
A friendly intro before the formal notes — no formulas yet.
Carbonyl Chemistry: Attack and Test
Aldehydes and ketones both contain a polar carbon-oxygen double bond (C=O), making the carbon atom a target for attack. We can tell them apart because aldehydes are easily oxidised, while ketones are not.
Imagine a checkout counter. The cashier (the oxygen atom) is very good at pulling money (electrons) towards them, leaving the till drawer (the carbon atom) slightly open and easy for a shopper (a nucleophile) to add something to. If the counter is at the end of an aisle (an aldehyde), a manager ([O]) can easily check and change it. If it's in the middle of two aisles (a ketone), it's much harder for the manager to access and alter.
- 1
Carbonyl C=O is polar — δ+ on C attracts nucleophiles.
- 2
Aldehydes oxidised to carboxylic acids; ketones resist oxidation.
- 3
Nucleophilic addition: CN⁻, HCN, NaBH₄ add to C=O.
- 4
Distinguish aldehyde vs ketone using oxidising agents in exams.
Explore the concept
Use the live diagram and synced steps — play it or tap a step card to walk through.
Key formulas
Tap any symbol to reveal exactly what it means and its units.
Full topic notes
Formal explanation with the rigour you need for the exam.
Structure, Bonding, and Nomenclature
Both aldehydes and ketones feature the carbonyl functional group, C=O. In aldehydes, the carbonyl group is bonded to at least one hydrogen atom, meaning it is always found at the end of a carbon chain. Their names end in '-al', e.g., ethanal. In ketones, the carbonyl group is bonded to two carbon atoms, so it is always found within a carbon chain. Their names end in '-one', e.g., propanone. The geometry around the carbonyl carbon is trigonal planar, with bond angles of approximately 120°. The C=O double bond consists of one sigma (σ) bond and one pi (π) bond.
Aldehyde: RCHO (carbonyl at end of chain). Suffix: -al.
Ketone: RCOR' (carbonyl within chain). Suffix: -one.
The high electronegativity of oxygen makes the C=O bond polar: C is and O is .
The carbon is an electrophilic centre, vulnerable to attack by nucleophiles.
Distinguishing Tests: Oxidation
The key difference in reactivity between aldehydes and ketones is their behaviour with oxidising agents. Aldehydes are easily oxidised to carboxylic acids, while ketones are resistant to oxidation. This difference is exploited in simple chemical tests to distinguish between them. We use mild oxidising agents so that other functional groups are not affected.
General Oxidation of an Aldehyde: RCHO(aq) + [O] RCOOH(aq)
Two common reagents are Tollens' reagent and Fehling's solution. With Tollens' reagent, [Ag(NH₃)₂]⁺, an aldehyde is oxidised, and the Ag⁺ ions are reduced to metallic silver, forming a beautiful silver mirror on the inside of the test tube. With Fehling's solution, a deep blue solution containing Cu²⁺ ions, an aldehyde is oxidised, and the Cu²⁺ ions are reduced to Cu⁺ ions, which form a brick-red precipitate of copper(I) oxide, Cu₂O, upon warming. Ketones give no reaction with either reagent.
Nucleophilic Addition Reactions
The most characteristic reaction of carbonyl compounds is nucleophilic addition. The electron-deficient () carbonyl carbon is attacked by a nucleophile (an electron-pair donor). In this process, the weak π-bond of the C=O group breaks, and its electrons move onto the electronegative oxygen atom, forming a negatively charged intermediate. This intermediate is then protonated, usually by a water molecule or a weak acid, to form the final product.
1. Addition of HCN
Aldehydes and ketones react with hydrogen cyanide (HCN) to form hydroxynitriles (also called cyanohydrins). This reaction is important as it increases the length of the carbon chain by one carbon atom. For safety and to ensure a sufficient concentration of the nucleophile, the reaction is typically carried out using a mixture of sodium or potassium cyanide (NaCN or KCN) and a weak acid like H₂SO₄. The KCN provides the nucleophilic cyanide ion (:CN⁻), and the acid provides the H⁺ for the final protonation step.
Mechanism with propanone: CH₃COCH₃ + HCN (CH₃)₂C(OH)CN
Step 1: The nucleophilic :CN⁻ ion attacks the electrophilic carbonyl carbon.
Step 2: The C=O π-bond breaks, and the electron pair moves to the oxygen, forming a negatively charged intermediate anion.
Step 3: The intermediate anion is protonated by an H⁺ ion (from HCN or H₂O) to form the hydroxynitrile product.
If the starting aldehyde or ketone is unsymmetrical (e.g., butanone), the product hydroxynitrile will have a new chiral centre. The nucleophilic attack can occur from above or below the planar carbonyl group with equal probability, resulting in the formation of a racemic mixture (a 50:50 mix of two enantiomers).
2. Reduction using NaBH₄
Aldehydes and ketones can be reduced to alcohols. A common reducing agent used in the lab for this purpose is sodium borohydride, NaBH₄. This reagent acts as a source of the hydride ion (:H⁻), which is a powerful nucleophile. The reaction is another example of nucleophilic addition. Aldehydes are reduced to primary alcohols, and ketones are reduced to secondary alcohols.
Aldehyde reduction: RCHO + 2[H] RCH₂OH (Primary Alcohol) Ketone reduction: RCOR' + 2[H] RCH(OH)R' (Secondary Alcohol)
Worked examples
See the formulas applied — reveal one step at a time, like the exam.
A student has two unlabelled bottles, one containing pentan-2-one and the other containing pentanal. Describe a chemical test to distinguish between these two compounds. State the expected observations for both compounds.
- 1
Method: Add about 1 cm³ of Tollens' reagent to a clean test tube containing a few drops of each unknown liquid. Warm the mixture gently in a water bath for a few minutes. [1 mark]
2.90 g of propanal (CH₃CH₂CHO) is reduced using an excess of NaBH₄ in an aqueous solution. Calculate the maximum mass of the organic product formed. ( values: C=12.0, H=1.0, O=16.0)
- 1
Step 1: Identify the product and write the equation. Propanal is an aldehyde, so it will be reduced to a primary alcohol, propan-1-ol. CH₃CH₂CHO + 2[H] CH₃CH₂CH₂OH [1 mark]
How it all connects
The big idea sits in the middle — tap a linked idea to explore the link.
Tap a linked idea to see how it connects back to the main topic — that connection is what examiners reward.
Glossary
Try to recall each definition before you reveal it.
Quick check
Answer in your head first — then tap to check. No pressure.
Revision flashcards
Flip the card. Test yourself before the exam.
What is a carbonyl group?
A functional group consisting of a carbon atom double-bonded to an oxygen atom (C=O).
Key takeaways
Review these before you close the topic — retrieval beats re-reading.
- ✓
Aldehyde: RCHO (carbonyl at end of chain). Suffix: -al.
- ✓
Ketone: RCOR' (carbonyl within chain). Suffix: -one.
- ✓
The high electronegativity of oxygen makes the C=O bond polar: C is and O is .
- ✓
The carbon is an electrophilic centre, vulnerable to attack by nucleophiles.
Practice — then mark it
The whole point: a real Cambridge question, marked mark-by-mark.
Practice Questions: Aldehydes & Ketones
Practice Questions: Aldehydes & Ketones
Extra simulations & links
PhET, GeoGebra and other curated tools — open in a new tab.
Frequently asked
Checkpoint
One marked question is worth ten re-reads — close the loop before you move on.
Reading it isn’t knowing it — prove it.
Before you move on: do Practice Questions: Aldehydes & Ketones on paper, snap a photo, and get examiner-style feedback on exactly where you win and lose marks.