In simple terms
A friendly intro before the formal notes — no formulas yet.
Monomer Clues: Addition or Condensation?
To predict how a polymer forms, you just need to inspect the monomer's structure. A carbon-carbon double bond signals addition, while two reactive functional groups signal condensation.
Imagine building a train. Addition polymerisation is like linking carriages that have magnetic couplers; they just click together and the train gets longer, with nothing lost. Condensation polymerisation is like linking older carriages that use a pin and hitch system; to join two carriages, you have to use the pin, and you're left with a spare hitch cover from each, which you discard. The train grows, but you also create a small pile of leftover parts.
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C=C monomer → addition polymerisation.
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Two functional groups → condensation.
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Diene + diene cross-link possible.
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Draw repeat unit with linkage atoms shown.
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Full topic notes
Formal explanation with the rigour you need for the exam.
Addition Polymerisation: The Unbroken Chain
Addition polymerisation is characterised by the joining of monomers without the loss of any atoms. The only requirement for a monomer to undergo this process is the presence of a carbon-carbon double bond (). During the reaction, the pi () bond within the double bond breaks, and the electrons are used to form new single bonds with adjacent monomer molecules. This creates a long, saturated carbon chain which forms the backbone of the polymer.
Monomer requirement: Must contain a double bond (i.e., be an alkene or substituted alkene).
Mechanism: The -bond breaks, and monomers add on, forming a long saturated chain.
Atom economy: 100%. No other product is formed.
Empirical formula: The empirical formula of the polymer is identical to that of the monomer.
Example: Ethene () polymerises to form poly(ethene) ().
Condensation Polymerisation: Building with a By-product
Condensation polymerisation involves a reaction between two functional groups. In this process, a covalent bond is formed between monomer units, and a small, stable molecule (like water, ammonia, or hydrogen chloride) is eliminated. For a chain to form, each monomer must be bifunctional, meaning it has two reactive functional groups. These can be two identical groups on one monomer that reacts with another bifunctional monomer (e.g., a diol with a dicarboxylic acid), or two different functional groups on a single monomer type (e.g., an amino acid).
Monomer requirement: Each monomer must have at least two reactive functional groups.
Common functional groups: Carboxyl (), hydroxyl (), amine (), and acyl chloride ().
Mechanism: Functional groups react, forming a linkage (e.g., ester, amide) and eliminating a small molecule.
Polymer types: Leads to polyesters (from diols and dicarboxylic acids) and polyamides (from diamines and dicarboxylic acids).
Example: Ethane-1,2-diol and terephthalic acid react to form the polyester Terylene, eliminating water.
A Simple Predictive Strategy
To determine the polymerisation route, follow a simple two-step check of the monomer(s). First, look for a double bond. If present, addition polymerisation is the most likely pathway. If there is no bond, or if the reaction conditions favour it, look for two reactive functional groups. If a monomer has two such groups (or you have two different monomers that are both bifunctional), condensation polymerisation will occur. A special case is a diene (a monomer with two bonds, e.g. buta-1,3-diene). This undergoes addition polymerisation, but the presence of a second double bond in each monomer unit allows for potential cross-linking between chains, as seen in the vulcanisation of rubber.
A common exam question gives you the structure of a polymer and asks you to identify the monomer(s). For an addition polymer, locate the repeating carbon backbone and mentally 're-form' the double bond between the two central carbons of the unit. For a condensation polymer, identify the ester or amide linkage and 'break' it by hydrolysis (adding ), adding -OH to the carbonyl carbon and -H to the oxygen or nitrogen atom to regenerate the original functional groups.
Worked examples
See the formulas applied — reveal one step at a time, like the exam.
The monomer chloroethene, , is used to make the polymer PVC. Predict the type of polymerisation it undergoes and draw two repeating units of the resulting polymer.
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Analyse the monomer: Chloroethene contains a double bond.
A polymer is formed from the monomers hexane-1,6-diamine, , and decanedioyl dichloride, . (i) Predict the type of polymerisation. (ii) Name the type of polymer formed and the linkage within it. (iii) Identify the small molecule eliminated. (iv) Draw the repeating unit of the polymer.
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(i) Prediction: The monomers are bifunctional (a diamine and a diacyl chloride). Their functional groups will react. This is condensation polymerisation. (ii) Polymer type and linkage: An amine reacts with an acyl chloride to form an amide linkage (). The polymer is a polyamide. (iii) Small molecule: The H from the amine group () and the Cl from the acyl chloride group () are eliminated as hydrogen chloride (). (iv) Repeating unit: The repeating unit consists of one of each monomer, joined by the amide link.
How it all connects
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Glossary
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Quick check
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Revision flashcards
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What is addition polymerisation?
A process where unsaturated monomer molecules add to a growing polymer chain one at a time, without the loss of any atoms. The empirical formula of the polymer is the same as the monomer.
Key takeaways
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Monomer requirement: Must contain a double bond (i.e., be an alkene or substituted alkene).
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Mechanism: The -bond breaks, and monomers add on, forming a long saturated chain.
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Atom economy: 100%. No other product is formed.
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Empirical formula: The empirical formula of the polymer is identical to that of the monomer.
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Example: Ethene () polymerises to form poly(ethene) ().
Practice — then mark it
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