In simple terms
A friendly intro before the formal notes — no formulas yet.
The Period 3 Property Parade
As you move from left to right across Period 3, from sodium to argon, the properties of elements change in a predictable pattern. This is because the number of protons increases, pulling electrons in tighter and changing how atoms bond with each other.
Imagine a tug-of-war team. As you go across Period 3, you keep adding more people (protons) to the 'pulling' team in the centre, but the rope (electron shell) stays the same length. The flag on the rope gets pulled closer and closer to the centre, just as the outer electrons are pulled closer to the nucleus, shrinking the atom's size.
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Atomic radius decreases across Period 3 as increasing nuclear charge pulls the outer electron shell closer.
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First ionisation energy generally rises due to stronger nuclear attraction, but dips at Group 13 (Al) and 16 (S) due to sub-shell changes and electron-pair repulsion.
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Melting point peaks at Group 14 (Si) because of its strong giant covalent structure, contrasting with the metallic and simple molecular elements.
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Electrical conductivity is high for the metals (Na, Mg, Al), then drops significantly for the semi-metal (Si) and non-metals (P, S, Cl, Ar) as mobile electrons become unavailable.
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Full topic notes
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Trend 1: Atomic and Ionic Radius
As we move from sodium to argon, a proton is added to the nucleus and an electron is added to the outer shell for each successive element. Crucially, all the outer electrons are in the third principal energy level (). The increasing number of protons leads to a greater nuclear charge. While there are more electrons, the shielding effect from the inner shells (n=1 and n=2) remains constant. Consequently, the electrostatic attraction between the nucleus and the outermost electrons strengthens, pulling the electron cloud in more tightly. This results in a steady decrease in atomic radius across the period.
Atomic Radius: Decreases from Na to Ar.
Reason: Increasing nuclear charge attracts the same outer shell () more strongly, with relatively constant shielding.
Ionic Radius: For cations (Na⁺, Mg²⁺, Al³⁺, Si⁴⁺), the radius decreases significantly as the nuclear charge increases for an isoelectronic series. For anions (P³⁻, S²⁻, Cl⁻), the radius also decreases for the same reason. Note that anions are much larger than cations in the same period, as they have an extra shell of electrons compared to the cations.
Trend 2: First Ionisation Energy
First ionisation energy is the energy required to remove one mole of electrons from one mole of gaseous atoms to form one mole of gaseous 1+ ions. The general trend across Period 3 is an increase. This is a direct consequence of the decreasing atomic radius and increasing nuclear charge. The outermost electron is held more tightly, so more energy is needed to remove it. However, there are two important exceptions to this smooth increase.
X(g) → X⁺(g) + e⁻
The first anomaly occurs between Group 2 (Magnesium) and Group 13 (Aluminium). Mg has the electron configuration [Ne]3s², while Al is [Ne]3s²3p¹. The electron removed from Al is from the 3p orbital, which is at a slightly higher energy level and is partially shielded by the 3s electrons. This makes it energetically easier to remove than one of Mg's 3s electrons.
The second anomaly is between Group 15 (Phosphorus) and Group 16 (Sulfur). P has the configuration [Ne]3s²3p³, with three unpaired electrons in the 3p subshell (a stable half-filled subshell). S is [Ne]3s²3p⁴, where one 3p orbital contains a pair of electrons. The repulsion between these two electrons in the same orbital makes it easier to remove one of them compared to removing an electron from a singly occupied orbital in phosphorus.
Trend 3: Melting Point & Structure
The melting point trend across Period 3 is not a simple increase or decrease. It is directly related to the change in bonding and structure from metallic to giant covalent to simple molecular.
- Na, Mg, Al: These are metals. Melting point increases as the strength of the metallic bond increases. This is due to the increasing number of delocalised electrons per atom (1 for Na, 2 for Mg, 3 for Al) and the increasing charge of the metal cation, leading to stronger electrostatic forces of attraction.
- Si: Silicon has a giant covalent structure, similar to diamond. To melt it, many strong covalent bonds must be broken, which requires a very large amount of energy. This gives Si the highest melting point in the period.
- P, S, Cl: These are non-metals that exist as simple discrete molecules (P₄, S₈, Cl₂). Their melting points are low because only weak intermolecular van der Waals' forces need to be overcome. The strength of these forces depends on the number of electrons in the molecule, so S₈ (more electrons) has a higher melting point than P₄, which is higher than Cl₂.
- Ar: Argon is a noble gas and exists as individual atoms (monatomic). The forces between atoms are extremely weak van der Waals' forces, resulting in a very low melting point.
When asked to explain trends in melting point or boiling point, always state the structure (e.g., giant metallic, simple molecular) and the specific type of bonding or force being broken or overcome (e.g., strong metallic bonds, weak van der Waals' forces).
Trend 4: Electrical Conductivity
Electrical conductivity depends on the presence of mobile charge carriers. The trend across Period 3 reflects the change in bonding.
- Na, Mg, Al: As metals, they possess a lattice of positive ions surrounded by a 'sea' of delocalised electrons. These electrons are mobile and can move through the structure to carry an electrical current. Conductivity increases from Na to Al due to the increasing number of delocalised electrons.
- Si: A metalloid, silicon is a semiconductor. Its electrons are held in covalent bonds, but a small number can gain enough thermal energy to break free and move, allowing for a small current to flow. Its conductivity is many orders of magnitude lower than metals.
- P, S, Cl, Ar: These are electrical insulators. Their electrons are either held tightly in covalent bonds (P, S, Cl) or within stable atoms (Ar). There are no mobile charge carriers, so they cannot conduct electricity.
Worked examples
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Explain why the first ionisation energy of Magnesium (12) is greater than that of Aluminium (13), despite Aluminium having a higher nuclear charge.
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State electron configurations: Mg is 1s²2s²2p⁶3s² and Al is 1s²2s²2p⁶3s²3p¹.
Arrange sodium, silicon, and sulfur in order of increasing melting point. Justify your answer in terms of structure and bonding.
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Order: The correct order of increasing melting point is Sodium < Sulfur < Silicon.
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Glossary
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What is periodicity?
The repeating pattern of physical and chemical properties of elements as you move across a period in the periodic table.
Key takeaways
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Atomic Radius: Decreases from Na to Ar.
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Reason: Increasing nuclear charge attracts the same outer shell () more strongly, with relatively constant shielding.
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Ionic Radius: For cations (Na⁺, Mg²⁺, Al³⁺, Si⁴⁺), the radius decreases significantly as the nuclear charge increases for an isoelectronic series. For anions (P³⁻, S²⁻, Cl⁻), the radius also decreases for the same reason. Note that anions are much larger than cations in the same period, as they have an extra shell of electrons compared to the cations.
Practice — then mark it
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9701/22 · Q1(b)
State and explain the difference in the ionic radius of Al compared to Mg.
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