In simple terms
A friendly intro before the formal notes — no formulas yet.
Uniform electric fields
Cambridge 9702 Paper 4 — Uniform electric fields (18.2). Senpai Corner diagram-backed pilot with premium structure and live visuals.
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18.2 Uniform electric fields.
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E is now also defined by the units Vm -1.
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The equation above can only be used for two charged parallel plates.
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A charged particle will move through an electric field due to a force on it that is caused by said electric field.
What this topic covers
The official Cambridge syllabus points this lesson works through.
- 18.2.1
Recall and use to calculate the field strength of the uniform field between charged parallel plates
- 18.2.2
Describe the effect of a uniform electric field on the motion of charged particles
Explore the concept
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Key formulas
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Tap a symbol — great for exam definitions
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Full topic notes
Formal explanation with the rigour you need for the exam.
What Makes a Field Uniform?
A uniform electric field is a special region where the electric force on a charged particle is the same in both strength and direction, no matter where the particle is located within that region. This consistency is represented visually by straight, parallel, and equally spaced electric field lines.
18.2 Uniform electric fields.
E is now also defined by the units Vm -1.
The equation above can only be used for two charged parallel plates.
A charged particle will move through an electric field due to a force on it that is caused by said electric field.
The trajectory, as shown in the diagram above is parabolic .
The direction of parabola depends on the charged of the particle.
Defining Electric Field Strength
At its core, electric field strength (E) quantifies the force exerted per unit of positive charge. This fundamental definition applies to all electric fields, uniform or not. When a charge 'q' is placed in a field 'E', it experiences a force 'F'.
or
Uniform Fields Between Parallel Plates
The most common way to create a uniform electric field is by applying a potential difference () across two large, parallel metal plates separated by a distance (). The field lines emerge perpendicularly from the positive plate and terminate perpendicularly on the negative plate.
This formula highlights that the electric field strength is also the magnitude of the potential gradient. It means for every metre you move across the field, the electric potential changes by 'E' Volts. The units for electric field strength can therefore be N C⁻¹ or V m⁻¹.
Equipotential Surfaces
Imagine contour lines on a map showing points of equal height. Equipotential surfaces (or lines in 2D) are similar, connecting all points within the field that have the same electric potential. In a uniform field, these are simple.
Equipotential lines are parallel to the charged plates.
They are always perpendicular to the electric field lines.
No work is done by the electric field when a charge moves along an equipotential line.
Work is done when a charge (Q) moves between different equipotentials ().
Motion of Charged Particles
When a charged particle enters a uniform electric field, it experiences a constant force (), much like the constant gravitational force on a mass near the Earth's surface. According to Newton's second law, this constant force produces a constant acceleration (). This allows us to use the standard kinematic equations (suvat) to predict the particle's motion. The trajectory depends on the initial velocity relative to the field.
Positive charges accelerate in the same direction as the field lines.
Negative charges accelerate in the opposite direction to the field lines.
If fired parallel to the field, motion is linear.
If fired perpendicular to the field, the path is parabolic, as the particle has constant horizontal velocity and constant vertical acceleration.
Worked examples
See the formulas applied — reveal one step at a time, like the exam.
Two parallel plates are separated by 2.0 cm and have a potential difference of 500 V across them. a) Calculate the electric field strength between the plates. b) What force does an electron (charge = C) experience in this field?
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Convert plate separation to metres: .
An electron (mass kg, charge C) is fired horizontally with a speed of m s⁻¹ into a uniform electric field. The field is created by two parallel plates, 5.0 cm long and 1.5 cm apart, with a potential difference of 300 V. Calculate the vertical deflection of the electron as it exits the plates.
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Calculate Electric Field Strength (E): The field is uniform between the plates.
How it all connects
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Glossary
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Quick check
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Revision flashcards
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What defines a uniform electric field?
A region where the electric field strength (E) is constant in both magnitude and direction.
Key takeaways
Review these before you close the topic — retrieval beats re-reading.
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18.2 Uniform electric fields.
- ✓
E is now also defined by the units Vm -1.
- ✓
The equation above can only be used for two charged parallel plates.
- ✓
A charged particle will move through an electric field due to a force on it that is caused by said electric field.
- ✓
The trajectory, as shown in the diagram above is parabolic .
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The direction of parabola depends on the charged of the particle.
Practice — then mark it
The whole point: a real Cambridge question, marked mark-by-mark.
9702/42 · Q5(c)
A proton is held at rest on the line joining the centres of the spheres in (b) at the position where x = 0.60 m. The proton is released. Describe and explain, without calculation, the subsequent motion of the proton.
9702/42 · Q9(b)
Determine an expression, in terms of m, q and V, for the momentum p of an electron in the beam.
Extra simulations & links
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Frequently asked
Checkpoint
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Reading it isn’t knowing it — prove it.
Before you move on: do 9702/42 · Q5(c) on paper, snap a photo, and get examiner-style feedback on exactly where you win and lose marks.