In simple terms
A friendly intro before the formal notes — no formulas yet.
Stress and strain
Cambridge 9702 Paper 2 — Stress and strain (6.1). Senpai Corner diagram-backed pilot with premium structure and live visuals.
- 1
Stress is symbolised by (sigma).
- 2
It measures the internal force acting on a material per unit cross-sectional area.
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The SI unit for stress is the Pascal (Pa), where 1 Pa = 1 N m⁻².
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High stress can be achieved with a large force or a very small area, explaining why sharp objects cut easily.
What this topic covers
The official Cambridge syllabus points this lesson works through.
- 6.1.1
Understand that deformation is caused by tensile or compressive forces (forces and deformations will be assumed to be in one dimension only)
- 6.1.2
Understand and use the terms load, extension, compression and limit of proportionality
- 6.1.3
Recall and use Hooke's law
- 6.1.4
Recall and use the formula for the spring constant
- 6.1.5
Define and use the terms stress, strain and the Young modulus
- 6.1.6
Describe an experiment to determine the Young modulus of a metal in the form of a wire
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Key formulas
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Full topic notes
Formal explanation with the rigour you need for the exam.
Deformation: The Basics
When a force acts on an object, its shape or size often changes – this is called deformation. Forces can either stretch an object, known as tensile forces, or squash it, called compressive forces. Think about pulling a spring (tensile) versus pressing down on a block (compressive).
Extension ($\\Delta L$ or $x$)
Extension, often symbolised as or , is simply how much longer an object gets from its original length after a tensile force is applied. It's a direct, absolute measure of the change in length.
Stress ($\\sigma$)
Stress tells us how concentrated the internal forces are within a material. It's not just about the total force, but how that force is distributed over a specific cross-sectional area. Imagine pushing a pin with your finger; the force is small, but the stress on the tip is huge!
Stress is symbolised by (sigma).
It measures the internal force acting on a material per unit cross-sectional area.
The SI unit for stress is the Pascal (Pa), where 1 Pa = 1 N m⁻².
High stress can be achieved with a large force or a very small area, explaining why sharp objects cut easily.
Strain ($\\epsilon$)
While extension tells us the absolute change in length, strain gives us a relative measure of deformation. It compares the amount of stretch to the object's initial size, making it a dimensionless quantity useful for comparing different objects regardless of their original dimensions.
is the extension (change in length).
is the original length.
Strain has no units (it is dimensionless) as it's a ratio of two lengths.
A larger strain value indicates a greater relative deformation.
Hooke's Law and the Spring Constant ($k$)
For many elastic materials, especially springs, there's a simple relationship between the applied force and the resulting extension, first observed by Robert Hooke. This law is crucial for understanding how objects behave within their elastic limits, provided temperature remains constant.
Hooke's Law: The force applied is directly proportional to the extension.
This law is valid up to the limit of proportionality.
The spring constant () indicates the stiffness of the object.
The unit for is Newtons per metre (N m); a higher means greater stiffness.
Elastic and Plastic Deformation
Materials can deform in two main ways. Elastic deformation is like stretching a rubber band – it returns to its original shape when you let go. But if you pull too hard, it might stretch permanently, entering plastic deformation, where it doesn't fully recover.
Elastic deformation: A temporary, reversible change in shape.
The elastic limit is the maximum force before permanent deformation occurs.
Plastic deformation: A permanent, irreversible change in shape.
Beyond the elastic limit, the material begins to 'yield' and deform plastically.
Elastic Potential Energy (EPE)
When you stretch or compress an elastic object, you do work on it, and this work is stored as elastic potential energy. This energy is released when the object returns to its original shape, for example, a stretched catapult launching a projectile.
EPE is the energy stored within a deformed elastic object.
It is equivalent to the work done to deform the object.
Represented by the area under a force-extension graph for linear regions.
The SI unit for EPE is Joules (J).
Young Modulus (E): Material Stiffness
To compare the inherent stiffness of different materials, we use the Young Modulus. Unlike the spring constant, which depends on the object's dimensions, Young Modulus is a fundamental property of the material itself. It's a ratio that normalises for the object's size and shape.
Defined as the ratio of stress to strain.
The SI unit for Young Modulus is Pascal (Pa).
Represents a material's inherent stiffness; a higher E means stiffer.
It is the gradient of the linear region on a stress-strain graph.
Ductile vs. Brittle Materials
Materials react differently when stretched to their breaking point. Ductile materials like copper can stretch a lot and undergo significant plastic deformation before fracturing. Brittle materials like glass, however, show very little plastic deformation and fracture suddenly with minimal stretching.
Ductile materials: Experience substantial plastic deformation before breaking.
Brittle materials: Fracture with very little or no plastic deformation.
Their behaviour is clearly visible on stress-strain graphs.
This distinction is crucial for material selection in engineering applications.
Loading and Unloading Graphs
When a material is loaded (stretched) and then unloaded (released), its behaviour can tell us if permanent deformation occurred. If the unloading curve doesn't return to the origin and instead shows residual extension, it signifies that plastic deformation has taken place.
The loading curve shows how the material deforms as force increases.
The unloading curve shows how it recovers as force decreases.
If plastic deformation occurs, the unloading curve will be parallel to the initial linear loading curve but will not return to the origin.
The area between the loading and unloading curves represents energy dissipated as heat during permanent deformation.
Worked examples
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A copper wire has an original length of 2.0 m and a cross-sectional area of 1.5 x 10 m. It is stretched by a tensile force of 45 N. Given that the Young Modulus for copper is 1.1 x 10 Pa, calculate the extension of the wire.
- 1
Recall the formula for Young Modulus: .
A steel rod of length 2.5 m and cross-sectional area 8.0 x 10⁻⁵ m² is subjected to a tensile force that causes it to extend by 1.2 mm. The Young Modulus of steel is 2.0 x 10¹¹ Pa. Calculate the elastic potential energy (EPE) stored in the rod.
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Identify the goal: Calculate Elastic Potential Energy (EPE). The formula is EPE = ½ * F * ΔL.
How it all connects
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Glossary
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Quick check
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Revision flashcards
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What is deformation?
Any change in an object's shape or size caused by applied forces.
Key takeaways
Review these before you close the topic — retrieval beats re-reading.
- ✓
Stress is symbolised by (sigma).
- ✓
It measures the internal force acting on a material per unit cross-sectional area.
- ✓
The SI unit for stress is the Pascal (Pa), where 1 Pa = 1 N m⁻².
- ✓
High stress can be achieved with a large force or a very small area, explaining why sharp objects cut easily.
Practice — then mark it
The whole point: a real Cambridge question, marked mark-by-mark.
9702/23 · Q3(e)
A second sample of the same material has a larger cross-sectional area than the original sample but the same initial length. The two samples are each deformed with the limit of proportionality. State and explain qualitatively how the spring constant of the second sample compares with that of the original sample.
9702/42 · Q3(b)(ii)
a wire is stretched within its elastic limit at constant temperature.
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