In simple terms
A friendly intro before the formal notes — no formulas yet.
The Periodic Table: A Map You Can Read
The periodic table is not a random chart — it is elements lined up in order of atomic number, and that single ordering makes their properties repeat in patterns. Once you know WHY a property changes (it almost always comes down to how strongly the nucleus pulls on the outer electrons), you can predict the behaviour of an element you have never met.
Think of the outer electrons as held by an elastic band anchored to the nucleus. Add protons to the nucleus and the pull gets stronger; add a whole new shell and the electrons sit further out and inner shells 'shield' them, so the pull feels weaker. Almost every trend on this page — size, ionization energy, electronegativity — is just this tug-of-war between a growing nuclear charge and a growing, shielding electron cloud.
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Fix an element's address: its period (row) is the highest principal energy level occupied; its group (column) sets the number of valence electrons; its block (s, p, d, f) is the sub-shell being filled.
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For any trend, ask three questions: is the nuclear charge changing, is the shielding (inner shells) changing, and is the radius changing?
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Across a period the nuclear charge rises but shielding barely changes, so the pull strengthens and atoms get smaller, harder to ionise and more electronegative.
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Down a group a new shell is added each time, so radius and shielding grow, the pull on the outer electron weakens, and metals become MORE reactive while non-metals become LESS reactive.
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Full topic notes
Formal explanation with the rigour you need for the exam.
Reading the table: periods, groups and blocks
The modern periodic table lists the elements in order of increasing atomic number Z. Its layout is a direct picture of electron configuration. The PERIOD (row) number equals the highest principal energy level occupied in the ground-state atom — so Period 3 elements are filling the n = 3 shell. The GROUP (column) number, in the main groups, tells you the number of valence electrons, which is why elements in the same group behave alike. And the table divides into BLOCKS named after the sub-shell being filled: the s-block (Groups 1–2), the p-block (Groups 13–18), the d-block or transition elements (Groups 3–12), and the f-block (the lanthanoids and actinoids drawn below the main body).
Period = highest occupied principal energy level (n). Sodium, [Ne]3s¹, is in Period 3.
Group = number of valence electrons (main groups). Sodium has one valence electron, so it is in Group 1.
Block = sub-shell being filled: s-block (Gp 1–2), p-block (Gp 13–18), d-block/transition (Gp 3–12), f-block (lanthanoids and actinoids).
Position and electron configuration are two views of the same fact — you can deduce one from the other.
Metals, non-metals and metalloids
The broadest classification is by metallic character — an element's tendency to LOSE electrons. A diagonal 'staircase' line, beginning between boron (B) and aluminium (Al), separates the table. Metals sit to the left, non-metals to the upper right, and a thin band of metalloids straddles the line. This is not just descriptive: it is the visible result of the trends we are about to explain, because losing electrons becomes easier towards the bottom-left (low ionization energy) and gaining them becomes easier towards the top-right (high electronegativity and electron affinity).
Metals (left of the staircase): shiny, good conductors, malleable and ductile; they LOSE electrons to form cations. Most elements are metals.
Non-metals (upper right, plus hydrogen): often dull, brittle, poor conductors; they GAIN or SHARE electrons to form anions or covalent bonds.
Metalloids (on the staircase: B, Si, Ge, As, Sb, Te): intermediate properties. Silicon is a semiconductor, central to electronics.
Metallic character increases DOWN a group and DECREASES across a period, so the most metallic elements lie bottom-left and the most non-metallic (excluding noble gases) lie top-right.
Atomic radius — the trend everything else follows
Atomic radius is the master trend, because the size of an atom controls how strongly its outer electrons are held. Across a period the radius DECREASES: each step adds a proton (raising the nuclear charge) while the extra electron joins the SAME outer shell and adds almost no shielding, so the growing effective nuclear charge (Z_eff) drags that shell inward. Down a group the radius INCREASES: each element begins a new, larger principal shell, and the extra inner shells add substantial shielding, so the outer electrons sit further out and are held more loosely. Keep this picture in mind — smaller atom means stronger pull on the outer electrons, and that single idea explains ionization energy, electronegativity and reactivity in turn.
Ionic radius
Forming an ion changes the size in a predictable way. A CATION is smaller than its parent atom: a metal usually loses its entire outer shell, and the remaining electrons feel the same nuclear charge shared among fewer electrons, so they are pulled in tighter — Na⁺ is much smaller than Na. An ANION is larger than its parent atom: adding electrons increases electron–electron repulsion and spreads the outer shell out, so Cl⁻ is larger than Cl. When comparing an ISOELECTRONIC series (ions with the same number of electrons, e.g. N³⁻, O²⁻, F⁻, Na⁺, Mg²⁺, Al³⁺, all with 10 electrons), the ion with the MOST protons is the smallest, because the same 10 electrons are pulled in by an increasing nuclear charge.
Cation < atom: electrons lost (often a whole shell); remaining electrons pulled in more tightly.
Anion > atom: electrons gained; extra repulsion expands the outer shell.
Isoelectronic series: same electron count, so more protons ⇒ smaller ion (Mg²⁺ < Na⁺ < F⁻ < O²⁻).
Down a group, ionic radius still increases (more shells), just as atomic radius does.
First ionization energy — and its two revealing dips
The first ionization energy (IE₁) is the energy needed to remove one mole of electrons from one mole of gaseous atoms: X(g) → X⁺(g) + e⁻. It is a direct measure of how tightly the outermost electron is held, so it tracks atomic radius. Across a period IE₁ generally INCREASES: nuclear charge rises, shielding is near-constant and the radius shrinks, so the outer electron is held more strongly and is harder to remove. Down a group IE₁ DECREASES: the outer electron is further from the nucleus and better shielded by more inner shells, so it is easier to remove. Superimposed on the general rise across a period are two small but important DIPS, and they are prized exam material because they are direct evidence for sub-shells and electron pairing.
General rise across a period: increasing nuclear charge + near-constant shielding + decreasing radius ⇒ stronger attraction ⇒ higher IE₁.
Fall down a group: increasing radius + increasing shielding ⇒ weaker attraction ⇒ lower IE₁.
Dip at Group 2 → 13 (e.g. Mg → Al): the electron removed is now a p electron, higher in energy and slightly shielded by the full s sub-shell, so less energy is needed.
Dip at Group 15 → 16 (e.g. P → S): the fourth p electron must pair up in an already-occupied orbital; the extra electron–electron repulsion makes it easier to remove.
Electronegativity and electron affinity
Electronegativity is the tendency of an atom to attract a shared pair of electrons in a covalent bond. It is a relative, unitless scale (Pauling), and it follows the radius story exactly: it INCREASES across a period (smaller atoms with higher nuclear charge pull bonding electrons more strongly) and DECREASES down a group (bonding electrons sit further from the nucleus and are more shielded). Fluorine, small and highly charged, is the most electronegative element at about 4.0; the noble gases are normally left off the scale because they rarely bond. Electron affinity is a closely related quantity — the enthalpy change when a gaseous atom gains an electron, X(g) + e⁻ → X⁻(g). It is usually exothermic (negative) and becomes MORE exothermic across a period, with the halogens releasing the most energy because a nearly-full outer shell strongly attracts an extra electron to complete the octet.
Electronegativity increases across a period, decreases down a group; F is the highest (~4.0), Cs/Fr among the lowest.
It measures attraction for a SHARED pair in a bond, so it applies to bonded atoms — it is not an energy.
Electron affinity is the enthalpy change for gaining an electron; generally more negative (more exothermic) across a period.
Halogens have the most exothermic electron affinities — one electron short of a full shell — which underpins their oxidising behaviour.
Group 1 and Group 17: opposite reactivity trends, one explanation
The alkali metals (Group 1: Li, Na, K, Rb, Cs) and the halogens (Group 17: F, Cl, Br, I) show the trends at their most vivid — and in OPPOSITE directions, which is a favourite exam contrast. Alkali metals react by LOSING their single outer electron to form +1 ions; going down the group that electron is further from the nucleus and more shielded, so it is lost more easily and reactivity INCREASES down the group (Cs is far more violent with water than Li). Halogens react by GAINING an electron to form −1 ions; going down the group the atom is larger, so an incoming electron ends up further from the nucleus and more shielded, is attracted less strongly, and reactivity DECREASES down the group (F₂ is the most reactive, the strongest oxidising agent). It is the same physics — distance and shielding weakening the nucleus's grip — producing opposite outcomes because one group loses and the other gains.
Group 1 (alkali metals): soft, low-density, low melting points; react with water to give H₂ and a hydroxide (alkaline solution); form +1 ions; reactivity INCREASES down the group.
Group 17 (halogens): reactive non-metals existing as diatomic molecules (F₂, Cl₂...); form −1 halide ions; act as oxidising agents; reactivity DECREASES down the group.
Displacement: a more reactive halogen displaces a less reactive one from solution (e.g. Cl₂ + 2KBr → 2KCl + Br₂), a direct demonstration of the trend.
Same underlying cause (radius and shielding), opposite direction, because Group 1 loses an electron and Group 17 gains one.
HL — The transition elements
The d-block metals (Groups 3–12) are the transition elements, defined more precisely as elements that form at least one stable ion with a partially filled d sub-shell. Because their 4s and 3d sub-shells lie close in energy, transition elements behave differently from the s-block metals in three signature ways. First, VARIABLE OXIDATION STATES: they can lose different numbers of electrons (iron forms both Fe²⁺ and Fe³⁺; manganese ranges up to +7 in MnO₄⁻). Second, COLOURED COMPLEXES: ligands split the d orbitals into two energy levels, and electrons absorb specific visible wavelengths jumping between them (d–d transitions), so [Cu(H₂O)₆]²⁺ is blue and [Ni(H₂O)₆]²⁺ is green. Third, CATALYSIS: their ability to change oxidation state easily and to offer empty d orbitals for bonding makes many of them catalysts — iron in the Haber process, vanadium(V) oxide in the Contact process, MnO₂ for decomposing hydrogen peroxide. By contrast, Group 1 and 2 metals show a single common oxidation state, form colourless ions and are not typical catalysts. (Note: scandium and zinc are d-block but are not usually counted as transition elements, because Sc³⁺ has an empty d sub-shell and Zn²⁺ has a full one.)
Definition (HL): a transition element forms at least one ion with a partially filled d sub-shell (so Sc and Zn are excluded).
Variable oxidation states: 4s and 3d close in energy ⇒ several accessible oxidation states (Fe²⁺/Fe³⁺, Cu⁺/Cu²⁺, Mn up to +7).
Coloured complexes: d-orbital splitting by ligands ⇒ d–d transitions absorb visible light ⇒ colour.
Catalysis: easy change of oxidation state and available d orbitals ⇒ many are catalysts (Fe, V₂O₅, MnO₂, Ni).
Common mistakes examiners penalise
Saying atomic radius INCREASES across a period — it decreases. The added electrons enter the same shell and add little shielding, so rising nuclear charge pulls that shell in and the atom shrinks left to right.
Claiming shielding rises sharply ACROSS a period — it is roughly constant across a period (same shell); shielding rises mainly DOWN a group as whole new shells are added. Confusing the two wrecks trend explanations.
Explaining IE₁ with 'more protons so it's harder' and nothing else — you must link the greater nuclear charge to the near-constant shielding and the smaller radius/stronger attraction. The bare 'more protons' statement is marked as too vague.
Forgetting the two IE dips — Group 2→13 (s→p sub-shell change) and Group 15→16 (electron pairing repulsion). Treating the period as a smooth rise loses the mark that tests sub-shell understanding.
Getting the two group reactivity trends backwards — alkali metals get MORE reactive down the group (lose an electron more easily), halogens get LESS reactive down the group (gain an electron less easily).
Saying metallic character DECREASES down a group — it increases down a group (and decreases across a period), because the outer electron becomes easier to lose lower down.
Calling hydrogen an alkali metal — it sits in Group 1 for its one valence electron but is a non-metal with unique behaviour.
Confusing electronegativity with ionization energy or electron affinity — electronegativity is a relative, unitless bonding tendency; the other two are energies (removing vs gaining an electron).
Model answer — marked the way our engine marks it
Explanation questions on periodicity are marked ANALYTICALLY: the mark scheme is a list of distinct valid points, and each independent, correct point you make scores one mark up to the total. There is a method/reasoning half (M — the mechanism) and an answer/conclusion half (A — the outcome you draw from it), and error-carried-forward (ECF) means a conclusion that follows correctly from an earlier (even mistaken) statement can still score. Study how the three marks below attach to three separate ideas, not to how many sentences you write.
Where this leads
Periodicity is the scaffolding for much of the course ahead. Ionization energies and electronegativities decide whether atoms form ionic or covalent bonds and how polar those bonds are (Structure 2); electron affinity and ionic radius feed directly into lattice enthalpies and Born–Haber cycles; and the group trends you have just explained underpin the chemistry of the s-block and p-block families. Master the single habit of arguing every trend from nuclear charge, shielding and radius, and you will be able to predict — not just recall — the behaviour of elements you meet later.
Worked examples
See the formulas applied — reveal one step at a time, like the exam.
An element has the ground-state electron configuration 1s²2s²2p⁶3s²3p⁴. Deduce its period, group and block, and name the element. [3]
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Step 1 — period. The highest principal energy level occupied is n = 3, so the element is in Period 3. [1]
Explain why the atomic radius of magnesium is smaller than that of sodium, but larger than that of chlorine. [3]
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Na → Mg (across a period, moving right): Sodium is [Ne]3s¹ and magnesium is [Ne]3s². Magnesium has one more proton, so a greater nuclear charge, while the extra electron is in the SAME 3s sub-shell and adds negligible shielding. The greater Z_eff pulls the outer shell in more tightly, so Mg is smaller than Na. [1]
The first ionization energies (kJ mol⁻¹) of four consecutive Period 3 elements are: Mg 738, Al 578, Si 786, P 1012. Explain why the value for Al is LOWER than that for Mg, despite aluminium having a greater nuclear charge. [2]
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The key is which electron leaves. In magnesium ([Ne]3s²) the electron removed comes from the 3s sub-shell. In aluminium ([Ne]3s²3p¹) the electron removed is the single 3p electron. [1]
Place the elements Li, K and Na in order of INCREASING reactivity with water, and place F, Cl and Br in order of INCREASING reactivity. Justify each order in terms of atomic structure. [3]
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Alkali metals (increasing reactivity): Li < Na < K. [1] Down Group 1 the outer electron is in a higher shell, further from the nucleus and more shielded by additional inner shells, so it is lost more easily — reactivity rises down the group, making K the most reactive of the three. [1]
Explain why the first ionization energy generally increases across Period 3 from sodium (Na) to argon (Ar). [3]
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Model answer. Across Period 3 the nuclear charge increases (from 11 protons in Na to 18 in Ar), while the electrons are added to the same outer principal energy level (n = 3), so the shielding by inner shells stays roughly constant. With a greater effective nuclear charge and near-constant shielding, the outer electrons are pulled in closer and the atomic radius decreases. Therefore the outermost electron is attracted more strongly and more energy is required to remove it, so the first ionization energy increases from Na to Ar.
How it all connects
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Glossary
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Quick check
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Revision flashcards
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Period
A horizontal row. The period number equals the highest principal energy level (n) that holds electrons in the ground-state atom. Period 3 = elements filling the n = 3 shell.
Key takeaways
Review these before you close the topic — retrieval beats re-reading.
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Period = highest occupied principal energy level (n). Sodium, [Ne]3s¹, is in Period 3.
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Group = number of valence electrons (main groups). Sodium has one valence electron, so it is in Group 1.
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Block = sub-shell being filled: s-block (Gp 1–2), p-block (Gp 13–18), d-block/transition (Gp 3–12), f-block (lanthanoids and actinoids).
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Position and electron configuration are two views of the same fact — you can deduce one from the other.
Practice — then mark it
The whole point: a real Cambridge question, marked mark-by-mark.
Get a Paper 2 periodicity explanation marked: explain a trend point-by-point with full reasoning
Get a Paper 2 periodicity explanation marked: explain a trend point-by-point with full reasoning
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