In simple terms
A friendly intro before the formal notes — no formulas yet.
Packing, Wrapping, and Finding Your Way Inside a Box
Volume is how much space a solid fills (how much water a bottle holds); surface area is the size of its outer skin (how much wrapping paper covers a box). Three-dimensional trigonometry is the skill of spotting a flat right-angled triangle hidden inside a solid and using it to find a length or an angle you cannot measure directly.
Picture a present in a box. Its volume is the space inside for the gift; its surface area is the paper needed to cover the outside. Now imagine a spider crawling corner-to-corner through the box along the longest straight line inside it — the space diagonal. To find that length, or the angle it makes with the floor, you look for the single right-angled triangle that contains it and solve that flat triangle on its own.
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Identify each solid and whether you need volume, surface area, a length, or an angle.
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For volume or surface area, pick the correct formula from the booklet and note what each letter (, , ) means.
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For a 3D angle or diagonal, isolate one right-angled triangle inside the solid, sketch it flat, and label its three sides.
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Substitute, then solve — leaving answers in terms of or as exact surds on Paper 1, and rounding to 3 significant figures when a decimal is required.
Explore the concept
Use the live diagram and synced steps — play it or tap a step card to walk through.
Key formulas
Tap any symbol to reveal exactly what it means and its units.
Full topic notes
Formal explanation with the rigour you need for the exam.
Prisms and cylinders
A right prism has a constant cross-section — imagine slicing a loaf where every slice is identical. Its volume is the area of that cross-section (the base) multiplied by the length. A cylinder is simply a prism with a circular base, so its volume is the area of the circle times the height.
Volume of a cylinder:
Surface area of a closed cylinder:
is the curved surface — the area you get by 'unrolling' the side into a rectangle of width (the circumference) and height .
is the combined area of the top and bottom circular ends.
For an open-topped cylinder (a tin with no lid) the surface area is — one circle, not two.
Pyramids and cones
Pyramids and cones taper to a point (the apex), and their volume is exactly one third of the prism or cylinder that would box them in. The crucial distinction here is between the perpendicular height , measured straight down from the apex to the centre of the base, and the slant height , measured down the sloping face. With the radius they form a right-angled triangle, so , and you will constantly use Pythagoras to swap between them. Volume needs ; curved surface area needs .
Volume of a cone:
Surface area of a cone: (curved surface + circular base)
Spheres and composite solids
A sphere is defined entirely by its radius, and so are its two formulas. Exam questions frequently glue solids together — a hemisphere on a cylinder to make a silo, a cone on a cylinder to make a pencil. For volume you simply add the parts. For surface area you must be selective: include only the surfaces on the outside, and drop every face hidden where two solids join.
Volume of a sphere:
Surface area of a sphere:
When finding the surface area of a composite solid, imagine painting it. You can only paint the outside. Where a cone sits on a cylinder of equal radius, the cone's base and the cylinder's top are internal and are NOT painted, so leave them out. A very common slip is to add a full hemisphere surface as but then also add its flat base — for a hemisphere sitting on a cylinder of equal radius, that flat face is hidden and must be excluded.
The space diagonal of a cuboid
The longest straight line inside a cuboid runs from one corner to the opposite corner, passing through the interior — the space diagonal. You find it with Pythagoras applied twice. First find the diagonal across the base rectangle; then treat that base diagonal and the vertical edge as the two shorter sides of a second right-angled triangle whose hypotenuse is the space diagonal. Combining the two steps gives a single neat formula.
Space diagonal of an cuboid:
Step 1 (base): the diagonal of the base rectangle is .
Step 2 (up to the far corner): the space diagonal is .
The same two-triangle idea (base diagonal, then rise) is what you use for the angle a diagonal makes with the base — see the next section.
Angles in 3D: line–line, line–plane, plane–plane
Every 3D angle question reduces to the same move: find one right-angled triangle that contains the angle, redraw it flat, and use SOH-CAH-TOA. What changes is how you build that triangle. The angle between two lines is measured directly between them where they meet (or where they would meet if extended). The angle between a line and a plane is the angle between the line and its projection — its 'shadow' — on the plane; you build it by dropping a perpendicular from the far end of the line onto the plane. The angle between two planes (the dihedral angle) is found along the line where they meet: from a point on that line, draw a line in each plane perpendicular to the meeting line, and measure the angle between them.
Line and plane: drop a perpendicular from the line's far point to the plane, join the foot to the base of the line to get the projection, then the required angle sits in that right-angled triangle. It is always the smallest angle the line makes with the plane.
Two planes (dihedral): identify the common edge; from one point on it, draw a perpendicular to that edge WITHIN each plane; the angle between those two perpendiculars is the dihedral angle.
Golden rule: redraw the single relevant right-angled triangle away from the solid, label all three sides, then choose sine, cosine or tangent.
Common mistakes examiners penalise
Using the slant height where the perpendicular height is needed (or vice versa) — cone volume needs ; curved surface area needs . Always link them with before substituting.
Confusing the sphere and cone volume formulas — sphere is (radius cubed, no height), cone is . Reading the wrong line of the booklet costs the method mark.
Forgetting to cube for volume or square for area — a cube of edge 2 has volume , not ; and the unit must be cubed (cm³) or squared (cm²) to match.
Including hidden faces in a composite surface area — the joined faces are internal and must be left out; only exposed surfaces are 'painted'.
Measuring a 3D angle from the wrong triangle — for a line and a plane, the angle is with the projection on the plane, not with a vertical edge or the space diagonal. Redraw the right-angled triangle flat before choosing a trig ratio.
Mixing units — convert all lengths to a single unit before calculating; a stray mm among cm silently wrecks a volume.
Over-rounding mid-calculation — carry extra figures through the working (keep exact) and round only the final answer to 3 significant figures.
Model answer — marked the way our engine marks it
In IB Mathematics the marks are analytic. A method mark (M) is earned for the correct approach — the right equation, the right triangle — even if the arithmetic later slips. An accuracy mark (A) is for a correct value and is DEPENDENT on the method being right (an A-mark cannot be earned without its M-mark). Follow-through (FT) means that once you have a wrong value, later marks are still awarded if your subsequent working is correct FOR THAT value. The engine also applies ISW ('ignore subsequent working') once a correct answer appears, accepts any equivalent exact form, and accepts a decimal that is correctly rounded to 3 significant figures. Study how each mark below is tied to a specific line.
Where this leads
The habit built here — reduce every solid to one right-angled triangle, redraw it flat, then use Pythagoras or a trig ratio — is exactly what the rest of the geometry and trigonometry unit demands. It feeds straight into the sine and cosine rules for non-right-angled triangles, into the area of a triangle with , and into arc-length and sector problems, all of which reuse the same 'find the triangle, label the sides, choose the ratio' method. Master it now and the later trigonometry becomes variations on a routine you already own.
Worked examples
See the formulas applied — reveal one step at a time, like the exam.
A closed cylindrical can has radius 4 cm and height 10 cm. Find, in terms of , its (a) volume and (b) total surface area. [4]
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(a) Volume. State the formula , then substitute , . [M1: correct substitution] cm³. [A1]
A right cone has base radius 5 cm and perpendicular height 12 cm. Find, in terms of , its (a) volume and (b) total surface area. [5]
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(a) Volume. Use with , . [M1: correct substitution] Since : cm³. [A1]
A toy is made from a hemisphere of radius 3 cm joined to the flat top of a cylinder of radius 3 cm and height 8 cm. Find, in terms of , the total volume of the toy. [4]
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Volumes add. Find each part, then sum.
A cuboid room ABCDEFGH has floor ABCD with AB = 6 m, BC = 4 m, and vertical height CG = 3 m. Find (a) the length of the space diagonal AG and (b) the angle that AG makes with the floor. Give answers to 3 significant figures. [5]
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(a) Space diagonal AG. Apply Pythagoras twice. Base diagonal: . [M1: Pythagoras across the base] Space diagonal: . m (3 s.f.). [A1]
A cone has base radius 5 cm and slant height 13 cm. Find its vertical (perpendicular) height, then its volume. Give the volume to 3 significant figures. [5]
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Model answer — full working.
How it all connects
The big idea sits in the middle — tap a linked idea to explore the link.
Tap a linked idea to see how it connects back to the main topic — that connection is what examiners reward.
Glossary
Try to recall each definition before you reveal it.
Quick check
Answer in your head first — then tap to check. No pressure.
Revision flashcards
Flip the card. Test yourself before the exam.
Volume vs surface area
Volume is the space a solid occupies, in cubic units (cm³, m³). Surface area is the total area of its outer surfaces, in square units (cm², m²).
Key takeaways
Review these before you close the topic — retrieval beats re-reading.
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is the curved surface — the area you get by 'unrolling' the side into a rectangle of width (the circumference) and height .
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is the combined area of the top and bottom circular ends.
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For an open-topped cylinder (a tin with no lid) the surface area is — one circle, not two.
Practice — then mark it
The whole point: a real Cambridge question, marked mark-by-mark.
Get a Paper 1 calculation marked: solve a 3D solids problem with full working
Get a Paper 1 calculation marked: solve a 3D solids problem with full working
Extra simulations & links
PhET, GeoGebra and other curated tools — open in a new tab.
Frequently asked
Checkpoint
One marked question is worth ten re-reads — close the loop before you move on.
Reading it isn’t knowing it — prove it.
Before you move on: do Get a Paper 1 calculation marked: solve a 3D solids problem with full working on paper, snap a photo, and get examiner-style feedback on exactly where you win and lose marks.