In simple terms
A friendly intro before the formal notes — no formulas yet.
A Line as an Address Plus a Heading
A vector equation of a line is a set of walking instructions: stand at a known point, then step any distance you like along a fixed direction. The point is your starting address; the direction is your heading; the parameter is how far you walk.
Think of setting a friend on a straight footpath. You do not list every paving slab — you say 'start at the postbox, then keep walking towards the church tower.' The postbox is the position vector , the heading towards the tower is the direction vector , and how many strides they take is the parameter . Every point on the path is 'postbox plus strides towards the tower', which is exactly .
- 1
Pin down one point that lies on the line. Its position vector from the origin is your anchor, .
- 2
Find a direction vector — any non-zero vector parallel to the line. Through two points, .
- 3
Assemble , where is a scalar that can be any real number.
- 4
Feed the equation: choose a to generate a point, or test a point by demanding a single that works in every component at once.
Explore the concept
Use the live diagram, PhET or GeoGebra sim, and synced steps — play it, drag controls, or tap a step.
Step 1
Pin down one point that lies on the line. Its position vector from the origin is your anchor, .
Key formulas
Tap any symbol to reveal exactly what it means and its units.
Full topic notes
Formal explanation with the rigour you need for the exam.
The anatomy of a vector equation of a line
To fix a line in space you need exactly two things: somewhere it passes through, and which way it points. The first is a point, captured by its position vector; the second is a direction, captured by a direction vector. Everything else on the line is reached by starting at the point and travelling some multiple of the direction.
Neither ingredient is unique. Any point on the line can serve as , and any scalar multiple of — larger, smaller, or reversed — is an equally good direction. So the very same line has infinitely many correct vector equations, which is why markers award full credit to any valid anchor-and-direction pair, not just the 'textbook' one.
is the position vector of a known, fixed point on the line (for example ).
is any non-zero vector parallel to the line — the direction vector.
(lambda) is a scalar parameter; as it ranges over all real numbers, sweeps out the entire line.
is the position vector of a general point on the line.
Parametric and Cartesian forms
The vector equation is compact, but its component form is what you actually compute with. Reading off each coordinate line by line gives the parametric form; eliminating the parameter from those three equations gives the Cartesian form, which is convenient for finding where a line meets a plane or surface.
Vector form:
Parametric form:
Cartesian form (each ):
If a direction component is zero — say — you cannot divide by it. Write that coordinate as a fixed equation and pair up the rest: with . Geometrically the line lies in the plane . Forcing a division by zero into the chained Cartesian form is a classic dropped mark.
The line through two points, and testing a point
Given two points, the direction is the vector from one to the other, — a subtraction, never an addition. Anchor at either point and you are done. To test whether some other point lies on the line, substitute it for and demand a single value of that satisfies every component at once: one stride length must set all three coordinates together.
The angle between two lines
The angle between two lines is the angle between their directions — where the lines actually sit in space is irrelevant, and they need not even meet. Use the scalar (dot) product of the direction vectors. Because a line points 'both ways', we always report the acute angle: if the cosine comes out negative, take the absolute value before applying .
, and the angle between the lines is (the acute angle).
Relationships between two lines
In three dimensions two lines fall into exactly one of three cases. They may be parallel (same direction, up to scaling), they may intersect at a single point, or they may be skew — non-parallel yet never meeting, like two aircraft on crossing headings but at different altitudes. Skewness is genuinely new in 3D; it cannot happen in a plane.
The method is always the same. First compare directions: proportional means parallel, and you are done. If not parallel, set the two equations equal, giving three component equations in the two unknowns and — use different letters for the two parameters, or the whole test collapses. Solve two of the equations, then substitute into the third: consistent means the lines intersect, and back-substitution gives the point; inconsistent means the lines are skew.
Parallel: the directions are scalar multiples, . Same in every component. (Share a point too, and the lines coincide.)
Intersecting: not parallel, and some unique solves in all three components.
Skew: not parallel, and the two-component solution for fails the third component — no common point exists.
Common mistakes examiners penalise
Adding position vectors instead of subtracting — the direction through and is , never . Adding gives a meaningless direction and derails everything after it.
Accepting a point on partial agreement — a point lies on a line only if ONE value of fits ALL components. Two out of three is a fail, not a pass.
Reusing one parameter for two lines — set and equal with DIFFERENT letters, and . Using for both forces a false constraint and invents an intersection that is not there.
Skipping the third-equation check — solving two component equations is not proof of intersection. Substitute the pair into the third: consistent ⇒ intersecting; inconsistent (and not parallel) ⇒ skew.
Mistaking proportional directions for 'different' lines — and are scalar multiples, so those lines are parallel, however different the numbers look.
Reporting the obtuse angle between lines — if , take the absolute value before so you give the acute angle the question wants.
Dividing by a zero component in Cartesian form — when some , write that coordinate as a separate equation (e.g. ) rather than dividing by zero.
Model answer — marked the way our engine marks it
On Paper 1 the marks are analytic: each is tied to a specific line of working — a method mark () for the correct approach, or an accuracy mark () for the right value, where an mark is dependent on the mark before it. Follow-through (FT) means that a right method carried out on a wrong earlier number still earns the marks that depend on it. But this protection only exists if the method is on the page. Study how each of the five marks below is earned by a specific line.
Worked examples
See the formulas applied — reveal one step at a time, like the exam.
A line passes through with direction . Determine whether the point lies on the line. [3]
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Write the line and substitute for , looking for one consistent .
Find the acute angle between the lines with direction vectors and . [4]
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Scalar product: . [M1: scalar product]
Consider and . Determine whether the lines are parallel, intersecting, or skew. If they intersect, find the point of intersection. [6]
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Check for parallelism. The directions are and . Is one a scalar multiple of the other? From the -components , but then the -components would need , which is false. Not parallel. [M1: directions compared]
Find a vector equation of the line through the points and , and determine whether the point lies on it. [5]
- 1
Model answer — full working.
How it all connects
The big idea sits in the middle — tap a linked idea to explore the link.
Tap a linked idea to see how it connects back to the main topic — that connection is what examiners reward.
Glossary
Try to recall each definition before you reveal it.
Quick check
Answer in your head first — then tap to check. No pressure.
Revision flashcards
Flip the card. Test yourself before the exam.
Vector equation of a line
, where is the position vector of a known point on the line, is a direction vector parallel to the line, is a scalar parameter, and is the position vector of a general point.
Key takeaways
Review these before you close the topic — retrieval beats re-reading.
- ✓
is the position vector of a known, fixed point on the line (for example ).
- ✓
is any non-zero vector parallel to the line — the direction vector.
- ✓
(lambda) is a scalar parameter; as it ranges over all real numbers, sweeps out the entire line.
- ✓
is the position vector of a general point on the line.
Practice — then mark it
The whole point: a real Cambridge question, marked mark-by-mark.
Get a Paper 1 question marked: find a line, test a point, or classify two lines with full working
Get a Paper 1 question marked: find a line, test a point, or classify two lines with full working
Frequently asked
Checkpoint
One marked question is worth ten re-reads — close the loop before you move on.
Reading it isn’t knowing it — prove it.
Before you move on: do Get a Paper 1 question marked: find a line, test a point, or classify two lines with full working on paper, snap a photo, and get examiner-style feedback on exactly where you win and lose marks.