In simple terms
A friendly intro before the formal notes — no formulas yet.
Calculus in Action: Finding the Best and the Fastest
Calculus isn't just abstract theory; it's a tool for two everyday questions. Optimisation asks 'what choice gives the best outcome?' — the biggest area, the least material. Kinematics asks 'how is this thing moving?' — where it is, how fast, speeding up or slowing down. Both come down to one idea: the derivative measures how a quantity is changing, and where that rate is zero something special happens.
Imagine building a rectangular garden with a fixed length of fencing but wanting the biggest area — calculus finds the exact dimensions. Now think of a car journey: its position is the displacement, the speedometer shows velocity (the rate of change of position), and pressing the accelerator or brake changes the acceleration (the rate of change of velocity). In both stories the interesting moments — the maximum area, the instant the car is momentarily still — are exactly where a derivative equals zero.
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Model the situation: identify the quantity to maximise or minimise (area, volume, cost) and write a formula for it; or, for motion, write down the displacement .
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Reduce to one variable: use any constraint to express the objective in terms of a single variable; or, for motion, differentiate to get and .
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Differentiate and solve: set the derivative to zero — for optimisation, for 'at rest' or maximum displacement — and solve.
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Justify and conclude: confirm a maximum or minimum with the second derivative or a sign diagram, or interpret the motion; then answer the actual question, with units.
Explore the concept
Use the live diagram, PhET or GeoGebra sim, and synced steps — play it, drag controls, or tap a step.
Step 1
Model the situation: identify the quantity to maximise or minimise (area, volume, cost) and write a formula for it; or, for motion, write down the displacement .
Key formulas
Tap any symbol to reveal exactly what it means and its units.
Full topic notes
Formal explanation with the rigour you need for the exam.
Part 1: Optimisation
Optimisation is the process of finding the best possible value of a quantity — the largest area, the greatest volume, the least cost or material. The strategy is always the same. Write the quantity you care about (the objective) as a function; if it depends on more than one variable, use a constraint to eliminate all but one; then differentiate, set the derivative to zero to find the stationary points, and justify whether each is the maximum or minimum you want. The justification is not optional: solving only finds candidates, and IB awards a reasoning mark for showing which candidate is genuinely the extremum.
Objective function: identify the quantity to optimise and write it as a function, e.g. for area or for cost.
Constraint: use the given fixed information (a perimeter, a volume, a length of fencing) to express the objective in terms of a single variable. This is usually the step candidates find hardest.
Differentiate and solve: compute the derivative and solve to locate the stationary points.
Justify and conclude: confirm a maximum with (or changing ) and a minimum with (or changing ), then re-read the question and state the answer it asked for, with units.
Part 2: Kinematics
Kinematics describes the motion of an object without worrying about the forces behind it. In this course the motion is along a straight line, and calculus links its three descriptions. The displacement says where the particle is relative to the origin; differentiating gives the velocity , which says how fast and in which direction it moves; differentiating again gives the acceleration , which says how the velocity is changing. Reading motion is then a matter of interpreting these functions: the particle is at rest where , its extreme displacements occur where , and the sign of tells you the direction of travel.
The core relationships are: Velocity: Acceleration: And, going the other way, by integration: Velocity: Displacement:
Displacement () is the signed position from the origin; it can be positive, negative or zero.
Velocity () is the rate of change of displacement. Positive means moving in the positive direction, negative the other way, and the particle is at rest when .
Acceleration () is the rate of change of velocity — the second derivative of displacement.
Maximum (or minimum) displacement occurs at a stationary point of , i.e. where ; substitute that time back into to get the value.
Total distance over an interval requires checking for a change of direction (where ), then summing the magnitudes of the displacement over each leg.
Connecting the two ideas
Optimisation and kinematics feel like different topics, but they are the same technique in different clothing. Finding the maximum displacement of a particle means finding a stationary point of — solving — which is exactly what you do to maximise an area or volume in optimisation. In both cases you differentiate, set the derivative to zero, and then justify or interpret what that stationary point means. Recognising this shared structure means you are really only learning one method, applied to two families of question.
Common mistakes examiners penalise
Saying a particle is at rest when — 'at rest' means . Setting finds when it is back at the origin, a different question entirely.
Treating acceleration as or an integral — acceleration is the DERIVATIVE of velocity, . Integrating goes the wrong way (that recovers displacement from velocity).
Solving but never justifying the nature of the point — the reasoning mark requires for a maximum or for a minimum (or a first-derivative sign diagram). No justification, no mark.
Confusing the constraint with the objective — optimise the quantity the question asks about, and use the fixed information only to eliminate a variable. Differentiating the constraint by mistake is a classic error.
Forgetting to reduce to a single variable before differentiating — you cannot apply the single-variable derivative to a function of two variables; substitute using the constraint first.
Confusing displacement with total distance — for total distance, split at every time where and add the magnitudes; do not just compute .
Dropping units or the constant of integration — quote answers with units, and when integrating or include and find it from an initial condition.
Model answer — marked the way our engine marks it
On Paper 1 the marks are analytic: each is tied to a specific line of working. A method mark (M) rewards a correct approach even if the arithmetic later slips; an accuracy mark (A) rewards a correct result and is usually dependent on the method mark being earned. Follow-through (FT) means a correct final step performed on your own earlier (wrong) value still scores, ISW ('ignore subsequent working') means a correct answer is not un-marked by a later fumble, and equivalent correct forms are accepted. All of that protection exists only if your method is on the page. Study how each mark below is earned by a specific line.
Where this leads
Everything here is one skill — differentiate, set the derivative to zero, interpret the result — applied to two contexts. That skill returns immediately in integration, where you reverse it to recover velocity and displacement from acceleration (remembering ), and in the area-under-a-curve problems that follow. Master the habit — model the quantity, reduce to one variable or differentiate for and , solve, then justify or interpret — and the rest of calculus becomes variations on a method you already own.
Worked examples
See the formulas applied — reveal one step at a time, like the exam.
A company is designing a cylindrical can that must hold a volume of . It wants to minimise the metal used, which is proportional to the total surface area. Find the radius and height that minimise the surface area, giving your answers to 3 significant figures, and justify that your answer is a minimum. [7]
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Let the radius be cm and the height be cm.
A particle moves along a straight line so that its displacement, metres, from a fixed point O at time seconds () is . (a) Find the initial displacement. (b) Find an expression for the velocity . (c) Find the time(s) when the particle is at rest. (d) Find the total distance travelled in the first 4 seconds. [8]
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(a) The initial displacement is . m. [A1]
A particle moves so that its displacement is metres, seconds. Find the times when the particle is at rest, and the acceleration at . [5]
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Model answer — full working.
How it all connects
The big idea sits in the middle — tap a linked idea to explore the link.
Tap a linked idea to see how it connects back to the main topic — that connection is what examiners reward.
Glossary
Try to recall each definition before you reveal it.
Quick check
Answer in your head first — then tap to check. No pressure.
Revision flashcards
Flip the card. Test yourself before the exam.
What is an optimisation problem in calculus?
A problem where you find the maximum or minimum value of a quantity, usually subject to a constraint. You write the quantity as a function, use the constraint to reduce it to one variable, then differentiate. Example: maximising the volume of a box made from a fixed amount of cardboard.
Key takeaways
Review these before you close the topic — retrieval beats re-reading.
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Objective function: identify the quantity to optimise and write it as a function, e.g. for area or for cost.
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Constraint: use the given fixed information (a perimeter, a volume, a length of fencing) to express the objective in terms of a single variable. This is usually the step candidates find hardest.
- ✓
Differentiate and solve: compute the derivative and solve to locate the stationary points.
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Justify and conclude: confirm a maximum with (or changing ) and a minimum with (or changing ), then re-read the question and state the answer it asked for, with units.
Practice — then mark it
The whole point: a real Cambridge question, marked mark-by-mark.
Get a Paper 1 calculation marked: solve a kinematics or optimisation problem with full working
Get a Paper 1 calculation marked: solve a kinematics or optimisation problem with full working
Extra simulations & links
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Frequently asked
Checkpoint
One marked question is worth ten re-reads — close the loop before you move on.
Reading it isn’t knowing it — prove it.
Before you move on: do Get a Paper 1 calculation marked: solve a kinematics or optimisation problem with full working on paper, snap a photo, and get examiner-style feedback on exactly where you win and lose marks.