In simple terms
A friendly intro before the formal notes — no formulas yet.
The Bell Curve: Nature's Favourite Shape
The normal distribution describes how data for many natural quantities — height, weight, measurement error — clusters around an average. Its graph is a symmetric, bell-shaped curve pinned down by just two numbers: the mean , which fixes the centre, and the standard deviation , which fixes the width.
Imagine lining up everyone in your year by height. Most people crowd around the average, forming a tall bulge in the middle; a few are unusually short or tall, thinning out into the tails. Trace a line over the tops of their heads and you get a bell. Move the whole line taller and the bell slides right (bigger ); make heights more varied and the bell flattens and widens (bigger ). Those two dials — centre and spread — are all you ever adjust.
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Read off the mean and standard deviation from the question, and write the model as .
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Sketch a quick bell curve, mark the mean, and shade the region whose probability you need. The sketch tells you which GDC function to use.
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For a probability, use the normal cumulative distribution function with the lower bound, upper bound, and . For a value from a probability, use the inverse normal with the area to the LEFT.
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Write down the GDC set-up before the answer, then round to three significant figures. A quick 68–95–99.7 check confirms the answer is sensible.
Explore the concept
Use the live diagram, PhET or GeoGebra sim, and synced steps — play it, drag controls, or tap a step.
Step 1
Read off the mean and standard deviation from the question, and write the model as .
Key formulas
Tap any symbol to reveal exactly what it means and its units.
Full topic notes
Formal explanation with the rigour you need for the exam.
Properties of the normal distribution
A random variable is normally distributed when its values follow a symmetric bell curve. The distribution is fixed by exactly two numbers: the mean , which locates the centre, and the standard deviation , which sets the width. We record this as . Read the notation carefully — the second entry is the variance , but every calculation uses the standard deviation , so if a question quotes a variance you must square-root it before touching the GDC.
Because is continuous, the probability of any single exact value is zero: probability is area, and a single point has no width. A useful consequence is that and are identical — you never have to worry about whether an endpoint is included.
The curve is bell-shaped and symmetric about the vertical line .
The mean, median and mode are all equal and sit at the centre, so .
The total area under the curve is exactly 1, and areas represent probabilities.
The curve approaches but never touches the horizontal axis, extending to in the tails.
shifts the curve left or right; stretches it — a larger gives a flatter, wider bell, a smaller a taller, narrower one.
Finding probabilities with the GDC
To find the probability that falls in an interval, you find the area under the bell over that interval. Doing this by hand needs advanced integration, so on Paper 2 you use the GDC's normal cumulative distribution function. You supply a lower bound, an upper bound, the mean and the standard deviation, and it returns the area between the bounds.
To find , use: \n normalCdf(lower: a, upper: b, μ: mean, σ: std dev)
For : set lower and upper (a stand-in for ).
For : set lower and upper .
For : use and directly.
Always write down the function and its four inputs — that is what earns the method mark, even if the final number slips.
The inverse normal: finding a value from a probability
Sometimes you are handed the probability — a percentage, a percentile, a 'top 10%' — and asked for the boundary value. This runs the previous idea backwards, so you use the inverse normal function. It takes an area to the LEFT of the unknown value, together with and , and returns the value for which equals that area.
To find the value such that , use: \n invNorm(area: p, μ: mean, σ: std dev)
The inverse normal always wants the area to the left of the value you seek.
'Bottom ' means — enter area .
'Top ' means , so the area to the left is — enter area .
A percentile is already an area to the left: the 90th percentile is the with .
Sketch and shade first — misreading which tail you want is the single most common error in this topic.
Standardising: the z-score
The standardised -score rewrites a value as the number of standard deviations it lies from the mean. If then a value has -score . A positive sits above the mean, a negative below, and is exactly at the mean. Standardising converts any normal variable into the standard normal , which is what lets you compare values that come from different distributions.
Standardised score: , so that becomes .
For example, a student scores 70 in a test with mean 60 and standard deviation 8, giving ; a friend scores 65 in a different test with mean 50 and standard deviation 10, giving . Although the raw score of 70 is higher, the friend's result is the more exceptional relative to its own distribution, because its -score is larger. On Paper 2 you can usually feed the original and straight into the GDC, but the -score is the tool for these comparison questions and for reasoning about how unusual a value is.
The 68–95–99.7 rule
Every normal distribution shares the same proportions once you measure distance in standard deviations. This is the empirical rule, and it gives fast estimates and a way to check GDC answers without a calculator.
About 68% of the data lies within 1 standard deviation of the mean, between and .
About 95% lies within 2 standard deviations, between and .
About 99.7% lies within 3 standard deviations, between and .
By symmetry, each tail beyond holds about of the data — a handy sanity check.
Use the rule to catch calculator slips. If you find where is two standard deviations above the mean, the answer must be near 0.025; anything far from that means a mis-typed bound or a swapped and . Estimate first, then trust the GDC only if the two agree.
Common mistakes examiners penalise
Entering the variance instead of the standard deviation — means , so enter , not 400. Always check whether the second parameter is a variance.
Using the wrong area in the inverse normal — the function wants area to the LEFT. For 'top 10%' enter 0.90, not 0.10; for a percentile enter the percentile itself as a decimal.
Getting the -score formula wrong — it is , subtracting the mean and dividing by the standard deviation, never dividing by the variance or reversing the subtraction.
Confusing which tail you need — 'more than', 'at least', 'fewer than' and 'top/bottom' each shade a different region. Sketch and shade before choosing bounds.
Forgetting the large-bound trick — needs an upper bound like ; leaving it blank or using twice returns zero or an error.
Not writing the GDC set-up — quoting only a final number forfeits the method mark. Show normalCdf(...) or invNorm(...) with its inputs.
Over-rounding mid-calculation — carry the full display and round only the final answer to 3 significant figures unless told otherwise.
Ignoring the 68–95–99.7 sanity check — an answer that contradicts the rule (a large tail beyond , say) is almost always a set-up error.
Model answer — marked the way our engine marks it
In Paper 2 the marks are analytic: each is tied to a specific line of working — a method mark (M) or an accuracy mark (A) — and an accuracy mark depends on the method mark it follows. Follow-through (FT) means an earlier wrong value need not cost you the marks that depend on it, provided the later step is carried out correctly on your figure. The engine also ignores subsequent working (ISW) once a correct answer appears, and accepts any equivalent form and any correctly-rounded value. But that protection only exists if the method is on the page. Study how each mark below is earned by a specific line — for the normal distribution, that means quoting the GDC function you used before the number it produced.
Where this leads
The normal distribution is where the descriptive statistics of earlier in the course become a working model: the mean you learned to read off a GDC is now , the centre of the bell, and the standard deviation is now , the dial that sets its width. Percentiles return as inverse-normal values, and the -score you meet here is the same standardising idea that underpins confidence intervals and hypothesis tests in the wider statistics course. Master the two-dial picture — a centre and a spread — together with the discipline of sketching the region, quoting the GDC function and checking against the 68–95–99.7 rule, and every normal-distribution question on Paper 2 becomes a variation on a method you already know how to write.
Worked examples
See the formulas applied — reveal one step at a time, like the exam.
The journey times, in minutes, for a student to travel to school are normally distributed with a mean of 32 minutes and a standard deviation of 5 minutes. Let the journey time be the random variable . \n (a) State the distribution of . \n (b) Find the probability that a randomly chosen journey takes between 30 and 40 minutes. \n (c) Find the probability that a journey takes more than 45 minutes. [5]
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(a) Distribution. Normal with and , so . [A1]\n\n**(b) .** Sketch a bell centred at 32 and shade between 30 and 40. Then\nnormalCdf(lower: 30, upper: 40, μ: 32, σ: 5) [M1]\n (3 s.f.). [A1]\n\n**(c) .** Shade the upper tail from 45 onwards, using a large upper bound:\nnormalCdf(lower: 45, upper: 1E99, μ: 32, σ: 5) [M1]\n (3 s.f.). [A1]\n\nA quick check: 45 is standard deviations above the mean, so by the 68–95–99.7 rule the tail beyond it should be well under 2.5% — and 0.00466 is.
The weights of newborn babies in a hospital are normally distributed with a mean of 3.4 kg and a standard deviation of 0.5 kg. Babies in the lightest 8% are monitored in a special care unit. Find the maximum weight for a baby to be placed in this unit. [3]
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Let be the weight of a newborn baby, so . [M1: correct parameters]\n\n'Lightest 8%' is the left tail, so we need with — the area 0.08 is already to the left, so no conversion is needed. A sketch confirms we want the low end of the curve.\n\ninvNorm(area: 0.08, μ: 3.4, σ: 0.5) [M1]\n\n\nThe maximum qualifying weight is kg (3 s.f.). [A1]
The mass of apples is grams. Find the probability an apple weighs more than 180 g, and the mass exceeded by only the heaviest 10%. [5]
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Model answer — full working.\n\nHere and , so .\n\nPart 1 — . Sketch the bell centred at 150 and shade the upper tail from 180. Using the normal cumulative distribution function with a large upper bound:\nnormalCdf(lower: 180, upper: 1E99, μ: 150, σ: 20)\n (3 s.f.).\n\n(Check: , so this is the tail beyond — small, as expected.)\n\nPart 2 — heaviest 10%. 'Heaviest 10%' means , so the area to the LEFT is ; equivalently we want the 90th percentile, . Using the inverse normal:\ninvNorm(area: 0.90, μ: 150, σ: 20)\n\n\nThe mass exceeded by only the heaviest 10% is g (3 s.f.) — sometimes quoted as g.\n\n---\nHow our marking engine awards the 5 marks:\n\n- M1 — set up . Awarded for a correct normal CDF set-up on the GDC — lower bound 180, an upper bound representing , with and . It is the set-up that is rewarded, so it survives even if the final figure is mistyped.\n- A1 — value . Awarded for (accept correctly-rounded equivalents such as or ). This accuracy mark depends on the M1 above.\n- M1 — inverse normal for the 90th percentile. A method mark for converting 'heaviest 10%' into an area to the left of and using invNorm with , . The engine checks that the area 0.90 (not 0.10) was used — that conversion is the crux of the mark.\n- A1 — value g. Awarded for g (accept g to 3 s.f., or the unrounded ). FT applies — a candidate who used a slightly different but correctly-converted area and read their GDC correctly earns this on their own figure.\n- A1 — full method and accuracy. The final mark rewards a complete, correctly-communicated solution: both GDC functions quoted with their inputs and both answers correctly rounded to 3 significant figures. A bare pair of numbers with no normalCdf/invNorm set-up risks losing the method marks entirely.\n\n**'Accept equivalent forms and correct rounding.'** The engine accepts or for the probability, and g, g or g for the mass. Once a correct answer appears, ISW means a later restatement does not lose marks.\n\nBottom line: of the 5 marks, two are method marks that survive an arithmetic or typing slip, and the accuracy marks are shielded by follow-through — but only if the normalCdf and invNorm set-ups are written down. A student who writes just '0.0668 and 175.6' with no working risks 2–3 marks; a student who shows the shaded sketch, the GDC function and the area conversion keeps the method whatever the final number does.
How it all connects
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Tap a linked idea to see how it connects back to the main topic — that connection is what examiners reward.
Glossary
Try to recall each definition before you reveal it.
Quick check
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Revision flashcards
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What is the normal distribution?
A continuous probability distribution whose graph is a symmetric, bell-shaped curve. It is completely determined by its mean (the centre) and standard deviation (the spread), and the total area under the curve is exactly 1.
Key takeaways
Review these before you close the topic — retrieval beats re-reading.
- ✓
The curve is bell-shaped and symmetric about the vertical line .
- ✓
The mean, median and mode are all equal and sit at the centre, so .
- ✓
The total area under the curve is exactly 1, and areas represent probabilities.
- ✓
The curve approaches but never touches the horizontal axis, extending to in the tails.
- ✓
shifts the curve left or right; stretches it — a larger gives a flatter, wider bell, a smaller a taller, narrower one.
Practice — then mark it
The whole point: a real Cambridge question, marked mark-by-mark.
Get a Paper 2 normal-distribution question marked: set up the GDC, use the inverse normal and show full working
Get a Paper 2 normal-distribution question marked: set up the GDC, use the inverse normal and show full working
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Frequently asked
Checkpoint
One marked question is worth ten re-reads — close the loop before you move on.
Reading it isn’t knowing it — prove it.
Before you move on: do Get a Paper 2 normal-distribution question marked: set up the GDC, use the inverse normal and show full working on paper, snap a photo, and get examiner-style feedback on exactly where you win and lose marks.