In simple terms
A friendly intro before the formal notes — no formulas yet.
Reverse the Slope, Add Up the Area
Integration is differentiation run backwards, plus a twist. Reversing a derivative recovers a whole family of functions that differ only by a constant, which is why every indefinite integral ends in . When you attach limits and evaluate, that same idea measures the area trapped between a curve and the x-axis.
Differentiation is like reading a car's speedometer from its position, moment by moment. Integration runs the film backwards: from the speed at every instant it rebuilds how far the car has travelled. But knowing only the speed does not tell you where the car started — that missing starting position is the constant . Give one fact about the journey (say, where it was at the start) and you can pin the constant down exactly. Geometrically, the distance covered is the area under the speed-time graph, and that is precisely what a definite integral computes.
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To integrate, reverse the power rule: add one to the power and divide by the new power, then write .
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If you know one point the function passes through, substitute it to find the value of and get the specific function.
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For an area or total, set up a definite integral with the correct limits and .
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Evaluate it — either by the antiderivative , or with the numerical integration function on your GDC.
Explore the concept
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Step 1
To integrate, reverse the power rule: add one to the power and divide by the new power, then write .
Key formulas
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Tap a symbol — great for exam definitions
Tap a symbol — great for exam definitions
Tap a symbol — great for exam definitions
Full topic notes
Formal explanation with the rigour you need for the exam.
Integration as the reverse of differentiation
Differentiation turns into . Integration undoes this: starting from it should recover . The catch is that , and all have the same derivative , because the derivative of a constant is zero. Reversing a derivative therefore cannot tell you which constant was originally present, so the result is a whole family of functions written with a constant of integration . This reversed process, with no limits attached, is called the indefinite integral, written .
You can always check an integral by differentiating the answer: if you get the integrand back, you were right.
The power rule for integration
Reversing the rule 'multiply by the power, then reduce the power by one' gives the rule for integrating a power of : add one to the power, then divide by the new power.
Add one to the power, divide by the new power. For the new power is , giving .
Integrate term by term. A sum is integrated one term at a time, e.g. (note that integrates to ).
The condition matters — the rule would divide by zero when , so needs a different result outside this lesson's scope.
Never drop the on an indefinite integral — it is the single most common mark lost in this topic.
Two mirror-image traps sit either side of the power rule. Differentiation reduces the power; integration raises it — so if your power went the wrong way you have applied the wrong operation. And every indefinite integral needs : writing with no constant is marked wrong even though is an antiderivative.
Finding a function from its derivative
Integration on its own leaves the unknown constant . If a question gives you one extra fact — a point the curve passes through, or an initial value — you can pin the constant down and recover the exact function. The routine is always the same: integrate to get the general form, substitute the known values, solve for , then write the specific function.
The definite integral and area under a curve
Attach a lower limit and an upper limit to the integral and it becomes a definite integral, , which evaluates to a single number rather than a family of functions. Its meaning is geometric: for a curve lying above the x-axis, it equals the area of the region bounded by the curve , the x-axis, and the vertical lines and . You can picture that area as a stack of infinitely thin rectangles of height and tiny width, summed across the interval.
The sign means 'sum up'; is the integrand and shows we integrate with respect to .
is the lower limit and the upper limit — the area runs from the line to the line .
To evaluate by hand, find an antiderivative and compute ; the constant cancels, so it is dropped for definite integrals.
A definite integral is a signed area: regions below the x-axis contribute negative values. For a genuine area, split at the x-intercepts and add the magnitudes.
On Paper 2 (calculator) evaluate definite integrals and areas straight from the GDC's numerical integration function — enter the integrand and the two limits and read off the value. Set the antiderivative up on paper first so the examiner sees the correct integral, then quote the GDC value. Watch the sign: a negative result usually signals a region below the x-axis, where 'area' needs the magnitude.
Common mistakes examiners penalise
Forgetting on an indefinite integral — is a family of functions; omitting the constant of integration loses the accuracy mark even when the antiderivative is right.
Applying the power rule the wrong way — integration ADDS one to the power and DIVIDES by the new power; reducing the power instead is differentiation in disguise.
Dividing by the wrong number — after raising the power to , divide by , not by the original (e.g. , not ).
Treating a signed integral as an area — a definite integral counts area below the x-axis as negative; for a true area, split at the x-intercepts and add the magnitudes.
Substituting the limits the wrong way round — evaluate as (upper minus lower); swapping them flips the sign of the answer.
Ignoring a boundary condition — 'find the function' questions need you to use the given point to find ; leaving the answer with in it is incomplete.
Dropping units or context — a volume, distance or area needs its units, and an accumulation question should be answered in the quantity it asked about.
Model answer — marked the way our engine marks it
IB awards marks analytically: each is tied to a specific line of working. A method mark (M) rewards a correct approach even if the arithmetic later slips; an accuracy mark (A) rewards a correct result and is usually dependent on the method mark being earned. Follow-through (FT) means a correct final step carried out on your own earlier (wrong) value still scores, and equivalent correct forms — including a value read straight from the GDC — are accepted. All of that protection exists only if your method is on the page. Study how each mark below is earned by a specific line.
Where this leads
Everything here is one idea seen from two sides: integration reverses differentiation, and evaluated between limits it measures area. That single tool carries straight into applications — integrating a velocity to recover displacement (remembering and an initial condition), integrating a rate to find a total accumulation, and finding the area between two curves by integrating the top curve minus the bottom. Master the habit — reverse the power rule, fix the constant from a condition, set up the definite integral with the right limits, then evaluate by hand or on the GDC — and the rest of integral calculus becomes variations on a method you already own.
Worked examples
See the formulas applied — reveal one step at a time, like the exam.
Find .
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Integrate term by term using the power rule. [M1: raise each power by one and divide]
A curve has gradient function and passes through the point . Find the equation of the curve. [4]
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Integrate the gradient function to get the general curve. [M1: attempt to integrate ] [A1: correct antiderivative including ]
The rate at which water flows into a tank is modelled by litres per minute, where is the time in minutes. Find the total volume of water that flows into the tank during the first 4 minutes. [4]
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Recognise this as a definite integral. The total volume is the accumulated flow, so integrate the rate from to . [M1: set up the definite integral with correct limits]
Find the area enclosed between the curve , the x-axis, and the lines and . [4]
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Model answer — full working.
How it all connects
The big idea sits in the middle — tap a linked idea to explore the link.
Tap a linked idea to see how it connects back to the main topic — that connection is what examiners reward.
Glossary
Try to recall each definition before you reveal it.
Quick check
Answer in your head first — then tap to check. No pressure.
Revision flashcards
Flip the card. Test yourself before the exam.
What is integration?
Integration is the reverse process of differentiation. Given a rate of change (a derivative), integrating recovers the original function; given a curve, a definite integral measures the area beneath it.
Key takeaways
Review these before you close the topic — retrieval beats re-reading.
- ✓
Add one to the power, divide by the new power. For the new power is , giving .
- ✓
Integrate term by term. A sum is integrated one term at a time, e.g. (note that integrates to ).
- ✓
The condition matters — the rule would divide by zero when , so needs a different result outside this lesson's scope.
- ✓
Never drop the on an indefinite integral — it is the single most common mark lost in this topic.
Practice — then mark it
The whole point: a real Cambridge question, marked mark-by-mark.
Get a Paper 2 integration problem marked: set up an integral or an area with full working
Get a Paper 2 integration problem marked: set up an integral or an area with full working
Extra simulations & links
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Frequently asked
Checkpoint
One marked question is worth ten re-reads — close the loop before you move on.
Reading it isn’t knowing it — prove it.
Before you move on: do Get a Paper 2 integration problem marked: set up an integral or an area with full working on paper, snap a photo, and get examiner-style feedback on exactly where you win and lose marks.