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A-Level Chemistry October/November 2024 Q2(c)(i): Explain the trend in the boiling points of the Group 16 hydrides H2S to H2Te.
A-Level Chemistry · Paper 9701/22 · October/November 2024 · Question 2(c)(i) · [2 marks]
Explain the trend in the boiling points of the Group 16 hydrides H2S to H2Te.
A full-marks model answer with a mark-by-mark examiner breakdown is below.
1 answer
- accepted ✓
The boiling points of the Group 16 hydrides increase from H₂S to H₂Te.
Going down the group from H₂S to H₂Te, the total number of electrons per molecule increases.
This results in stronger instantaneous dipole-induced dipole forces (or London dispersion forces) between the molecules. Consequently, more energy is required to overcome these stronger intermolecular forces, leading to an increase in the boiling point.
How the marks are awarded
- B1 — The first mark is for correctly identifying that as you go down the group from H₂S to H₂Te, the molecules have an increasing number of electrons.
- B1 — The second mark is for linking the greater number of electrons to stronger instantaneous dipole-induced dipole / London dispersion forces, and stating that more energy is needed to overcome them.
Common mistakes
- Discussing H₂O and hydrogen bonding, which is not part of the specific trend from H₂S to H₂Te requested in the question.
- Incorrectly attributing the trend primarily to changes in permanent dipole-dipole forces instead of the dominant effect of increasing London dispersion forces.
- Confusing intermolecular forces with intramolecular bonds by stating that covalent bonds are broken during boiling.
- Using vague terms like 'molecules get bigger' or 'stronger van der Waals' forces' without explicitly mentioning the number of electrons and specifying 'instantaneous dipole-induced dipole forces'.
Examiner tip: For trends in boiling points of simple molecular substances, always connect the total number of electrons in the molecule to the strength of the resulting London dispersion forces.
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