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A-Level Chemistry October/November 2024 Q4(c)(i): Write an ionic equation for this reaction, using the formulae of the complex ions.
A-Level Chemistry · Paper 9701/41 · October/November 2024 · Question 4(c)(i) · [2 marks]
Write an ionic equation for this reaction, using the formulae of the complex ions.
A full-marks model answer with a mark-by-mark examiner breakdown is below.
1 answer
- accepted ✓
The reaction is a ligand exchange where cyanide ions displace ammonia ligands from the tetraamminecadmium(II) complex.
The balanced ionic equation is:
[Cd(NH3)4]2+ + 4CN- → [Cd(CN)4]2− + 4NH3Working:
- Identify Reactants and Products: The initial complex is
[Cd(NH3)4]2+. It reacts with cyanide ions,CN-. This is a ligand substitution reaction, so theNH3ligands are replaced byCN-ligands, forming a new complex and releasingNH3. - Determine Oxidation State of Central Metal: In
[Cd(NH3)4]2+, ammonia (NH3) is a neutral ligand (charge = 0). Therefore, the oxidation state of cadmium (Cd) is +2 to give the overall 2+ charge. - Determine Formula of Product Complex: The oxidation state of Cd remains +2. Cyanide (
CN-) is a uninegative ligand (charge = -1). Assuming the coordination number remains 4, the new complex will be[Cd(CN)4]. The charge is calculated as:(charge of Cd) + 4 * (charge of CN-) = (+2) + 4 * (-1) = -2. So the product complex is[Cd(CN)4]2-. - Balance the Equation: To form one
[Cd(CN)4]2-ion, fourCN-ions are needed. These displace the fourNH3ligands from one[Cd(NH3)4]2+ion. This gives the final balanced equation.
How the marks are awarded
- B1 — The first mark is awarded for the fully correct and balanced ionic equation, showing correct formulae for all species ([Cd(NH3)4]2+, CN-, [Cd(CN)4]2−, NH3), correct charges, and correct stoichiometry (1:4:1:4).
- B1 — The second mark is awarded for correctly identifying the formula and charge of the product complex ion as [Cd(CN)4]2−, which is a key component of the overall correct equation.
Common mistakes
- Incorrectly calculating the charge of the product complex, for example writing
[Cd(CN)4]2+by copying the reactant's charge, or[Cd(CN)4]with no charge. - Incorrect stoichiometry, such as not balancing the number of
CN-ligands added andNH3ligands displaced (e.g., using a 1:1 ratio). - Omitting the square brackets for the complex ions or the charges on the ions, which are essential components of the formulae.
- Including spectator ions (e.g.,
Na+from a NaCN reactant) in an equation that specifically asks for the ionic form.
Examiner tip: Always calculate the charge of a product complex ion by summing the oxidation state of the central metal ion (which doesn't change in ligand exchange) and the total charge of the new ligands.
AI-generated model answer, grounded in the official Cambridge mark scheme and reviewed by the MarkScheme team. Mark your own answer to this question →
- Identify Reactants and Products: The initial complex is
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