In simple terms
A friendly intro before the formal notes — no formulas yet.
The Secret Code of Polynomials
The coefficients of a polynomial equation hold a secret code about its roots. Vieta's formulas allow us to crack this code, revealing properties like the sum and product of roots without ever having to find them individually.
Imagine a locked safe (the polynomial) and you don't have the keys (the roots). However, you're given clues on the outside of the safe (the coefficients) that tell you the total weight of all the gold bars inside (the sum of roots) and their combined volume (the product of roots). You can learn a lot about the contents without ever opening the safe.
- 1
Identify the polynomial's coefficients, ensuring it's in the form .
- 2
Apply Vieta's formulas to find the fundamental sums of roots (, , etc.), watching the signs.
- 3
Identify the target expression you need to find (e.g., ) or the transformation for a new equation.
- 4
Use algebraic identities to express your target in terms of the fundamental sums, or perform a substitution to find a new equation.
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Key formulas
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Full topic notes
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Vieta's Formulas: The Core Relationships
For any polynomial equation, the coefficients are intrinsically linked to the sums and products of its roots. Vieta's formulas provide the exact expressions for these links. The key is to look at the coefficients in order, divide by the leading coefficient, and apply an alternating sign pattern.
Quadratic: For with roots : <br> <br>
Cubic: For with roots : <br> <br> <br>
Quartic: For with roots : <br> <br> <br> <br>
Always check for missing terms in the polynomial. For example, in , the coefficients of and are both zero. So, . This is a very common place to lose marks.
Evaluating New Symmetric Sums
The real power of Vieta's formulas is in finding the values of other symmetric expressions—expressions which remain unchanged if you swap the roots around. A classic example is finding the sum of the squares of the roots, . We can't get this directly from Vieta's formulas, but we can derive it using them.
Consider the expansion of . For a cubic with roots : Rearranging gives the crucial identity:
Transformation of Roots
Another key skill is to find a new polynomial equation whose roots are related to the roots of an original equation. For example, if the original equation has roots , we might want to find the equation with roots or . The method involves a clever substitution.
Worked examples
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The equation has roots . Find the values of: (i) (ii) (iii)
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First, identify the coefficients of the cubic . Here, .
The roots of the equation are . Find the value of .
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The equation is a quartic with .
The equation has roots . Find a cubic equation with integer coefficients whose roots are .
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Let the original equation be , where can be or .
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Quadratic: For with roots : <br> <br>
Cubic: For with roots : <br> <br> <br>
Quartic: For with roots : <br> <br> <br> <br>
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