In simple terms
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Transport of oxygen and carbon dioxide
Cambridge 9700 Paper 2 - Transport of oxygen and carbon dioxide (8.2). A-Level Notes diagram-backed lesson with premium structure and live visuals.
- 1
The S-shaped curve demonstrates cooperative binding of oxygen to haemoglobin.
- 2
High pO₂ in the lungs (13.3 kPa) results in high haemoglobin saturation.
- 3
Low pO₂ in the tissues (e.g., 5.3 kPa) causes significant oxygen release.
- 4
The steep part of the curve ensures efficient oxygen unloading to active tissues.
What this topic covers
The official Cambridge syllabus points this lesson works through.
- 8.2.1
Describe the role of red blood cells in transporting oxygen and carbon dioxide with reference to the roles of: • haemoglobin • carbonic anhydrase • the formation of haemoglobinic acid • the formation of carbaminohaemoglobin
- 8.2.2
Describe the chloride shift and explain the importance of the chloride shift
- 8.2.3
Describe the role of plasma in the transport of carbon dioxide
- 8.2.4
Describe and explain the oxygen dissociation curve of adult haemoglobin
- 8.2.5
Explain the importance of the oxygen dissociation curve at partial pressures of oxygen in the lungs and in respiring tissues
- 8.2.6
Describe the Bohr shift and explain the importance of the Bohr shift
Explore the concept
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Full topic notes
Formal explanation with the rigour you need for the exam.
The Marvel of Haemoglobin
Haemoglobin (Hb) is the primary molecule responsible for oxygen transport in your blood. Found within red blood cells, it's a globular protein with a remarkable structure. It's a quaternary protein, meaning it's composed of four polypeptide chains: two alpha (α) chains and two beta (β) chains. Each polypeptide chain is associated with a non-protein haem prosthetic group, which contains a central iron (Fe²⁺) ion. It's this Fe²⁺ ion that reversibly binds to an oxygen molecule. Since there are four haem groups per haemoglobin molecule, each haemoglobin can carry up to four oxygen molecules, forming oxyhaemoglobin (HbO₂). Haemoglobin's ability to bind oxygen strongly in high partial pressures of oxygen (pO₂) in the lungs and release it readily in low pO₂ in the tissues is crucial for life.
Oxygen Transport: The Dissociation Curve
The relationship between the partial pressure of oxygen (pO₂) and the percentage saturation of haemoglobin with oxygen is represented by the oxygen dissociation curve. This curve is typically S-shaped (sigmoidal), reflecting haemoglobin's property of cooperative binding. When the first oxygen molecule binds to haemoglobin, it causes a conformational change that increases the affinity of the remaining binding sites for oxygen. This makes it easier for subsequent oxygen molecules to bind, leading to a steep rise in saturation.
Hb + 4O₂ ⇌ Hb(O₂)₄
In the lungs, where pO₂ is high (around 13.3 kPa), haemoglobin becomes almost 100% saturated with oxygen. In the tissues, where cells are respiring and pO₂ is much lower (e.g., 5.3 kPa at rest), haemoglobin readily releases its oxygen. The steep part of the curve indicates that a small drop in pO₂ in the tissues leads to a significant release of oxygen, perfectly supplying active cells.
The S-shaped curve demonstrates cooperative binding of oxygen to haemoglobin.
High pO₂ in the lungs (13.3 kPa) results in high haemoglobin saturation.
Low pO₂ in the tissues (e.g., 5.3 kPa) causes significant oxygen release.
The steep part of the curve ensures efficient oxygen unloading to active tissues.
The Bohr Effect: Shifting the Curve
Active tissues produce more carbon dioxide and heat, which influence haemoglobin's oxygen affinity. The Bohr effect describes how an increase in partial pressure of carbon dioxide (pCO₂), a decrease in pH (more acidic), and an increase in temperature all reduce haemoglobin's affinity for oxygen. These conditions cause the oxygen dissociation curve to shift to the right. This 'right shift' means that at any given pO₂, haemoglobin will release more oxygen. This is a vital adaptation: in metabolically active tissues, oxygen is released precisely where and when it's most needed for respiration.
Remember, a 'right shift' of the oxygen dissociation curve means a reduced affinity of haemoglobin for oxygen, leading to more oxygen being released to the tissues. Think 'R' for Right, 'R' for Reduced affinity, 'R' for Released!
Carbon Dioxide Transport: A Complex Journey
Carbon dioxide (CO₂) produced during tissue respiration must be transported to the lungs for excretion. It's carried in the blood in three main ways:
- Dissolved in plasma (~10%): A small amount of CO₂ dissolves directly in the blood plasma.
- Bound to haemoglobin (~20%): CO₂ can bind reversibly to the amino groups on the globin chains of haemoglobin, forming carbaminohaemoglobin. This binding occurs more readily with deoxygenated haemoglobin, which is prevalent in the tissues.
- As hydrogencarbonate ions (~70%): This is the most significant method. Inside red blood cells, CO₂ is converted to carbonic acid, which then dissociates. The resulting hydrogencarbonate ions are transported in the plasma.
The Chloride Shift: Maintaining Balance
The chloride shift is a vital mechanism that ensures electrical neutrality across the red blood cell membrane during carbon dioxide transport. As hydrogencarbonate ions (HCO₃⁻), which are negatively charged, move out of the red blood cell into the plasma, an equal number of negatively charged chloride ions (Cl⁻) move into the red blood cell. This prevents a charge imbalance that would otherwise hinder the continuous movement of HCO₃⁻ out of the cell, allowing efficient transport of CO₂ as hydrogencarbonate ions to the lungs. In the lungs, the process reverses: HCO₃⁻ moves back into the red blood cell, and Cl⁻ moves out.
Most CO₂ is converted to HCO₃⁻ in red blood cells.
HCO₃⁻ diffuses out into the plasma.
Cl⁻ ions move into red blood cells to maintain electrical neutrality (chloride shift).
H⁺ ions are buffered by deoxygenated haemoglobin.
The reverse process occurs in the lungs, releasing CO₂ for exhalation.
Worked examples
See the formulas applied — reveal one step at a time, like the exam.
An athlete is exercising vigorously. The partial pressure of oxygen () in their lungs is 13.3 kPa, and the in their active muscle tissue drops to 2.5 kPa. Given that the oxygen-carrying capacity of their blood is 20 of per 100 of blood, calculate the volume of oxygen delivered to the muscles per 100 of blood. Use the following data from the oxygen dissociation curve:
- At = 13.3 kPa, haemoglobin saturation is 98%.
- At = 2.5 kPa, haemoglobin saturation is 25%.
- 1
Step 1: Determine the oxygen saturation in the lungs and muscles.
- Saturation in lungs (leaving alveoli) = 98%
- Saturation in muscles (active tissue) = 25%
Describe the series of events that leads to the transport of carbon dioxide as hydrogencarbonate ions from a respiring tissue to the lungs, including the roles of carbonic anhydrase and the chloride shift.
- 1
CO₂ entry: Carbon dioxide diffuses from respiring tissue cells, across the tissue fluid, and into the red blood cells, as well as dissolving in the plasma.
How it all connects
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Glossary
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Quick check
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Revision flashcards
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Describe the quaternary structure of haemoglobin.
Haemoglobin is a globular protein made of four polypeptide chains (two alpha and two beta chains). Each chain has a haem prosthetic group containing an iron ion (Fe²⁺) that binds to one oxygen molecule.
Key takeaways
Review these before you close the topic — retrieval beats re-reading.
- ✓
The S-shaped curve demonstrates cooperative binding of oxygen to haemoglobin.
- ✓
High pO₂ in the lungs (13.3 kPa) results in high haemoglobin saturation.
- ✓
Low pO₂ in the tissues (e.g., 5.3 kPa) causes significant oxygen release.
- ✓
The steep part of the curve ensures efficient oxygen unloading to active tissues.
Practice — then mark it
The whole point: a real Cambridge question, marked mark-by-mark.
9700/22 · Q5(c)
One desirable feature of artificial blood products, such as artificial red blood cells, is that they should be economical to produce. Suggest other desirable features of artificial blood products.
9700/23 · Q3(b)(ii)
Suggest and explain how a steep oxygen concentration gradient is maintained in the lungs.
Extra simulations & links
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