In simple terms
A friendly intro before the formal notes — no formulas yet.
The Speed at an Instant
Differentiation is the tool that measures how fast something is changing at one precise moment. It is the mathematical version of glancing at a speedometer: not your average speed over a whole journey, but exactly how fast you are going right now. That same idea, the derivative, also measures the steepness of a curve at a single point.
Picture driving from one city to another. Your average speed for the trip might be 60 km/h — total distance over total time. But at any single instant your speedometer might read 70, 50, or 0 in a jam. That live reading is your instantaneous speed. Differentiation is the speedometer for any changing quantity: it turns a formula for where you are into a formula for how fast that quantity is changing.
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Draw a curve for a changing quantity — the height of a plant, the cost of production, the position of a car.
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The gradient of the straight line joining two points on it gives the average rate of change over that interval.
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Slide the two points together until they touch at one place: the line becomes the tangent to the curve.
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The gradient of that tangent is the derivative — the instantaneous rate of change, which the power rule lets us calculate exactly.
Explore the concept
Use the live diagram, PhET or GeoGebra sim, and synced steps — play it, drag controls, or tap a step.
Step 1
Draw a curve for a changing quantity — the height of a plant, the cost of production, the position of a car.
Key formulas
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Tap a symbol — great for exam definitions
Full topic notes
Formal explanation with the rigour you need for the exam.
The derivative: a gradient and a rate of change
Start with a quantity that changes, say the height of a growing plant. Measuring its height at the start and end of a week gives its average rate of growth — the gradient of the straight line (the secant) joining the two points. But the plant grew faster on sunny days and slower on cloudy ones, so to know its growth rate at one exact moment we let the two points slide together until the secant becomes a tangent touching the curve at a single point. The gradient of that tangent is the derivative: the instantaneous rate of change. These are two descriptions of the same number — the derivative is simultaneously the gradient of the curve and the rate of change of the quantity.
Average rate of change over (gradient of secant): Instantaneous rate of change at (gradient of tangent):
We write the derivative of in two interchangeable notations. Lagrange's notation (say 'f-prime of x') is compact and good for evaluating at a point, as in . Leibniz's notation (say 'dee-y by dee-x') makes the units obvious, because it literally reads as a change in over a change in .
The power rule
For polynomials and simple powers there is a fast, exact rule. To differentiate a single term, multiply by the current power and then reduce the power by one.
The power rule:
Differentiate term by term. For a polynomial, apply the power rule to each term and add: .
A constant differentiates to . A constant term has a horizontal graph (gradient ), so the above simply disappears.
A linear term differentiates to . Since , the power rule gives .
Negative and fractional powers work the same way — just rewrite first. , and .
The rule multiplies THEN reduces. , not and not — a very common slip.
Evaluating the gradient at a point
The derivative is itself a function — a formula for the gradient at any . To get the gradient at one specific point, substitute that -value into . The result, , is a single number: the gradient of the curve, and the instantaneous rate of change, at .
Interpreting the derivative in a real context
The reason the derivative matters is that it measures a real rate of change. When a quantity is modelled by a function, its derivative tells you how fast that quantity is changing — and the units come straight from the model: (units of ) per (unit of ). A full interpretation always states three things: the value, whether the quantity is increasing (positive derivative) or decreasing (negative derivative), and the units.
Common mistakes examiners penalise
Applying the power rule the wrong way round — it is multiply by the power THEN reduce it. , not (forgot to reduce) and not (forgot to multiply).
Thinking the derivative of a constant is the constant — . The in vanishes; carrying it through is a classic error.
Differentiating a fraction or root without rewriting it first — turn into and into BEFORE applying the power rule.
Confusing with — the gradient at a point is , found by substituting into the DERIVATIVE, not the height found from the original function.
Forgetting to substitute — leaving the answer as the derivative expression when the question asked for the gradient at a specific point. You must plug the value in and give a number.
Interpreting a rate without units or direction — a real-context answer needs the number, the units (units of per unit of ), and whether the quantity is increasing or decreasing. A bare number loses the interpretation mark.
Model answer — marked the way our engine marks it
In the exam the marks are analytic: each one is tied to a specific line of working. A method mark (M) rewards a correct approach — here, applying the power rule and substituting — even if the arithmetic later slips. An accuracy mark (A) rewards a correct result and is usually dependent on the method mark being earned first. Follow-through (FT) means that if you differentiate wrongly but then correctly substitute your own derivative, you still earn the substitution and final marks on your figure. All of that protection exists only if the method is written on the page. Study how each mark below is earned by a specific line.
Where this leads
Everything here is one skill — differentiate with the power rule, then read the result as a gradient or a rate of change. That skill is the gateway to the rest of calculus: setting to find the stationary points of a curve (maxima and minima), using the derivative to build the equation of a tangent line, and later reversing the process through integration to recover a quantity from its rate of change. Master the habit — rewrite as powers, differentiate term by term, substitute, then interpret with units — and the calculus that follows becomes variations on a method you already own.
Worked examples
See the formulas applied — reveal one step at a time, like the exam.
Differentiate the following with respect to . (a) (b) [6]
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(a) Apply the power rule to each term; the constant differentiates to . [M1: power rule on each term] . [A1]
A curve has equation . Find the gradient of the curve at the point where . [3]
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Differentiate to get the gradient function: . [M1: power rule, A1 implied by correct expression] Substitute : . [M1: substitute ] The gradient of the curve at is . [A1]
The height of a firework, metres, above the ground seconds after launch is modelled by for . (a) Find an expression for . (b) Find the rate of change of height at and at , and interpret each value in context. [6]
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(a) Differentiate the model term by term: . [M1: power rule; A1] The units are metres per second (m/s), the rate of change of height.
A curve is given by . Find and the gradient of the curve at . [4]
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Model answer — full working.
How it all connects
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Tap a linked idea to see how it connects back to the main topic — that connection is what examiners reward.
Glossary
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Quick check
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Revision flashcards
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What is a derivative?
The derivative of a function at a point gives the instantaneous rate of change of the function there, and equals the gradient of the tangent to the curve at that point.
Key takeaways
Review these before you close the topic — retrieval beats re-reading.
- ✓
Differentiate term by term. For a polynomial, apply the power rule to each term and add: .
- ✓
A constant differentiates to . A constant term has a horizontal graph (gradient ), so the above simply disappears.
- ✓
A linear term differentiates to . Since , the power rule gives .
- ✓
Negative and fractional powers work the same way — just rewrite first. , and .
- ✓
The rule multiplies THEN reduces. , not and not — a very common slip.
Practice — then mark it
The whole point: a real Cambridge question, marked mark-by-mark.
Practice finding and interpreting rates of change with full working
Practice finding and interpreting rates of change with full working
Extra simulations & links
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Frequently asked
Checkpoint
One marked question is worth ten re-reads — close the loop before you move on.
Reading it isn’t knowing it — prove it.
Before you move on: do Practice finding and interpreting rates of change with full working on paper, snap a photo, and get examiner-style feedback on exactly where you win and lose marks.