In simple terms
A friendly intro before the formal notes — no formulas yet.
The Water Park of Circuits
A circuit moves charge the way a water park moves water. A pump lifts water and gives it energy; pipes and slides carry it and slow it down. Swap 'water' for 'charge' and you have a working mental model of every DC circuit.
A pump (the battery) raises water to a height, giving each litre energy — that energy per unit of charge is the electromotive force. The litres passing a point each second are the current. Slides and narrow pipes (resistors) oppose the flow, and a long thin pipe opposes it more than a short fat one — exactly what resistivity describes. The height the water actually falls through in the external pipes is the terminal potential difference, and it is a little less than the full pump height because the pump itself wastes some energy internally (internal resistance).
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Start from the two things you can measure directly: current (flow of charge) and potential difference (energy given up per unit charge).
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Link them through resistance with Ohm's law, , for any component at a fixed temperature.
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Combine components: resistances add in series, but in parallel the extra paths make the total resistance fall below the smallest branch.
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Account for the real source: subtract the 'lost volts' inside the battery to get the terminal potential difference actually delivered to the circuit.
Explore the concept
Use the live diagram, PhET or GeoGebra sim, and synced steps — play it, drag controls, or tap a step.
Step 1
Start from the two things you can measure directly: current (flow of charge) and potential difference (energy given up per unit charge).
Key formulas
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Tap a symbol — great for exam definitions
} \frac{1}{R_{\text{total}}} = \frac{1}{R_1} + \frac{1}{R_2} + \ldots
Full topic notes
Formal explanation with the rigour you need for the exam.
Charge, current and potential difference
Electric current is the rate at which charge flows past a point. If a charge passes in a time , the current is , measured in amperes (1 A = 1 C s⁻¹). By convention we take current as the direction positive charge would move, even though in a metal it is electrons that drift the other way. Potential difference is the partner idea: it measures energy, not flow. The p.d. across a component is the electrical energy converted to other forms per unit charge passing through it, , measured in volts (1 V = 1 J C⁻¹).
Current is a flow of charge; potential difference is energy transferred per unit charge.
Electromotive force is energy SUPPLIED per unit charge by a source; p.d. is energy USED per unit charge in a component. Both are in volts.
Conventional current flows from + to − in the external circuit; electron flow is opposite.
Charge is conserved: it is neither created nor destroyed as it moves round a circuit.
Resistance, Ohm's law and resistivity
Resistance measures how strongly a component opposes current, defined as and measured in ohms (). For many conductors at constant temperature the current is proportional to the p.d.: this is Ohm's law, written with constant. Resistance also depends on the physical shape and material of a conductor. A longer wire has more resistance and a thicker wire has less, captured by the resistivity relation , where is the resistivity of the material (unit m), its length and its cross-sectional area.
Ohm's law applies only to ohmic conductors at constant temperature — it is not universal.
Resistance length and : doubling the length doubles ; doubling the cross-sectional area halves .
Resistivity is a property of the MATERIAL; resistance is a property of a particular SAMPLE of it.
Rearrange Ohm's law freely: and .
Ohmic and non-ohmic behaviour: I–V characteristics
An I–V characteristic is a graph of current against potential difference for a component. Its shape tells you at a glance whether the component obeys Ohm's law. A metal resistor at constant temperature gives a straight line through the origin — its resistance () is constant, so it is ohmic. A filament lamp gives an S-shaped curve that flattens as the voltage rises: heating the filament raises its resistance, so it is non-ohmic. A diode is strongly non-ohmic — it conducts almost nothing until a threshold forward voltage, then the current rises steeply, and it blocks current in the reverse direction. For any point on any of these graphs the resistance is still ; only for the straight ohmic line is that ratio constant.
Resistor (ohmic): straight line through the origin; constant resistance.
Filament lamp (non-ohmic): curve that flattens; resistance increases as it heats up.
Diode (non-ohmic): negligible current below the threshold voltage, then a steep rise; blocks reverse current.
Resistance at any point is always (the reciprocal gradient of a line from the origin), not the gradient of the curve itself.
Resistors in series and parallel
In series, components form a single path, so the SAME current flows through each and the source p.d. is shared between them; resistances simply add. In parallel, components connect across the same two points, so each has the SAME p.d. across it and the current splits between the branches; here the reciprocals of the resistances add. Because extra parallel paths make it easier for charge to flow, the combined parallel resistance is always smaller than the smallest single branch — a fact worth using as a check on every parallel calculation.
Electrical power
Power is the rate at which electrical energy is transferred. Combining (energy per charge times charge per second) with Ohm's law gives three equivalent forms. Use whichever version fits the two quantities you already know: when you have p.d. and current, when you have current and resistance, and when you have p.d. and resistance. All give power in watts (W).
EMF, internal resistance and terminal potential difference
A real cell is not a perfect source. It has an internal resistance in series with an ideal EMF . When a current flows, some energy is dissipated inside the cell, producing 'lost volts' equal to . The voltage actually available to the external circuit — the terminal potential difference — is therefore , which is also just the p.d. across the external load. For a single external resistor the EMF is shared between load and internal resistance, giving .
EMF is the total energy per unit charge supplied by the source.
'Lost volts' is the p.d. dropped across the internal resistance.
Terminal p.d. : always less than when current flows, and equal to only when (open circuit).
A graph of against is a straight line with intercept and gradient .
Kirchhoff's laws
Kirchhoff's two laws are the bookkeeping rules that let you analyse any circuit, however it is wired. The first law (the junction rule) says the total current flowing into any junction equals the total current flowing out — nothing more than conservation of charge, and the reason series current is constant while parallel current splits. The second law (the loop rule) says that around any closed loop the sum of the EMFs equals the sum of the potential-difference drops — a statement of conservation of energy, since a unit charge returning to its start must have gained exactly as much energy as it lost.
First law (junction / charge): at every junction.
Second law (loop / energy): around every closed loop.
The junction rule explains why current is the same all round a series loop and why branch currents add up in parallel.
The loop rule explains why the shared p.d.s across series resistors add up to the source's terminal p.d.
Common mistakes examiners penalise
Thinking current is 'used up' in series — current is identical everywhere in a single loop (conservation of charge). It is ENERGY that is transferred at each resistor, not current.
Forgetting to invert the parallel result — adding reciprocals gives , not . Always take the final reciprocal, and check the total is below the smallest branch.
Setting terminal p.d. equal to EMF — whenever current flows there are 'lost volts' , so . They are equal only on open circuit.
Treating a filament lamp or diode as ohmic — these are non-ohmic; their resistance changes, so you cannot use a single fixed and their I–V graphs are curved.
Confusing EMF with potential difference — EMF is energy supplied per unit charge by the source; p.d. is energy dissipated per unit charge in a component.
Mixing up the power formula — and are not interchangeable inputs: use the current with and the p.d. across THAT resistor with .
Confusing resistivity and resistance — resistivity is a material property (unit m); resistance depends on the sample's length and area through .
Model answer — marked the way our engine marks it
This is the showcase for a calculation topic. In Paper 2 the marks are analytic: each is tied to a specific piece of working — a method mark (M) or an answer mark (A) — and, crucially, the method marks and error-carried-forward (ECF) mean a wrong number early on does not cost you every mark that follows. That protection only exists if your method is written down. Study how each mark below is earned by a specific line.
Where this leads
The habits built here — track the current with Kirchhoff's junction rule, track the energy with the loop rule, and reach for the right form of the power equation — carry straight into the rest of electricity. Potential dividers are just series p.d.-sharing used deliberately; capacitor and RC work reuses charge, current and energy; and electromagnetic induction generates the very EMFs you have learned to handle here. Master the three-step circuit method — combine the resistances, find the current, then work out each p.d. — and the harder circuit questions become variations on a method you already own.
Worked examples
See the formulas applied — reveal one step at a time, like the exam.
A 12 V battery of negligible internal resistance is connected to a 4.0 Ω resistor in series with a parallel combination of a 12 Ω resistor and a 6.0 Ω resistor. Calculate (a) the total resistance of the circuit, (b) the current drawn from the battery, and (c) the current in the 6.0 Ω resistor. [6]
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Step 1 — combine the parallel pair. , so . [M1 method, A1 value]
A resistor of resistance 15 Ω carries a steady current of 0.40 A. (a) Calculate the potential difference across it. (b) Calculate the power dissipated, and confirm your answer by a second method. [4]
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Step 1 — potential difference (Ohm's law). . [M1 method, A1 value]
A battery of EMF 9.0 V and internal resistance 1.5 Ω is connected to an external resistor of 6.0 Ω. Calculate (a) the current in the circuit, (b) the terminal potential difference, and (c) the power dissipated inside the battery. [5]
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Step 1 — current from the loop equation. , so . [M1, A1]
A cell of EMF 6.0 V and internal resistance 0.50 Ω is connected to a 2.5 Ω resistor. Calculate the current in the circuit and the terminal potential difference. [3]
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Model answer — full working.
How it all connects
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Tap a linked idea to see how it connects back to the main topic — that connection is what examiners reward.
Glossary
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Quick check
Answer in your head first — then tap to check. No pressure.
Revision flashcards
Flip the card. Test yourself before the exam.
Electric current ()
The rate of flow of electric charge: . Unit: ampere (A), where . Conventional current is the direction positive charge would move.
Key takeaways
Review these before you close the topic — retrieval beats re-reading.
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Current is a flow of charge; potential difference is energy transferred per unit charge.
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Electromotive force is energy SUPPLIED per unit charge by a source; p.d. is energy USED per unit charge in a component. Both are in volts.
- ✓
Conventional current flows from + to − in the external circuit; electron flow is opposite.
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Charge is conserved: it is neither created nor destroyed as it moves round a circuit.
Practice — then mark it
The whole point: a real Cambridge question, marked mark-by-mark.
Get a Paper 2 circuit calculation marked: find the current and terminal potential difference with full working
Get a Paper 2 circuit calculation marked: find the current and terminal potential difference with full working
Extra simulations & links
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Frequently asked
Checkpoint
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Reading it isn’t knowing it — prove it.
Before you move on: do Get a Paper 2 circuit calculation marked: find the current and terminal potential difference with full working on paper, snap a photo, and get examiner-style feedback on exactly where you win and lose marks.