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A-Level Physics October/November 2024 Q9(a)(iii): Determine the activity of 2.1 × 10⁻¹²kg of fluorine-18.
A-Level Physics · Paper 9702/41 · October/November 2024 · Question 9(a)(iii) · [3 marks]
Determine the activity of 2.1 × 10⁻¹²kg of fluorine-18.
A full-marks model answer with a mark-by-mark examiner breakdown is below.
1 answer
- accepted ✓
Step 1: Calculate the number of nuclei (N)
The mass of a single fluorine-18 nucleus is its mass number (18) multiplied by the atomic mass unit ().
Mass of one nucleus, kg
The total number of nuclei, , in a sample of mass kg is given by:
Step 2: Calculate the activity (A)
The activity is given by the formula , where is the decay constant. From the previous part of the question, .
Bq
Bq (to 2 s.f.)
How the marks are awarded
- C1 — Stating the correct formula to find the number of nuclei (N), which involves dividing the total mass of the sample by the mass of a single fluorine-18 nucleus (18u).
- C1 — Correctly substituting the given mass (2.1 × 10⁻¹² kg) and the mass of a single nucleus (18 × 1.66 × 10⁻²⁷ kg) to calculate the number of nuclei, N.
- A1 — Using the activity formula A = λN with the calculated value of N and the decay constant to find a final answer of 7.4 x 10⁹ Bq.
Common mistakes
- Using the mass number (18) alone instead of the mass in kg (18 × u), leading to an incorrect calculation for N e.g., N = (2.1 × 10⁻¹²) / 18.
- Mixing units when using Avogadro's constant, for example, using the mass in kg with the molar mass in g/mol without conversion.
- Using the atomic number (9) instead of the mass number (18) for the mass of the nucleus.
- Making a calculation error when dealing with powers of ten, or a rounding error that leads to an incorrect final answer.
Examiner tip: For multi-step calculations, clearly lay out each stage with the relevant formula before substituting values to minimise errors and secure method marks.
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