Worked example 1
Calculate the theoretical maximum ATP yield from the complete aerobic respiration of one molecule of glucose. Assume that each reduced NAD yields 2.5 ATP and each reduced FAD yields 1.5 ATP.
Show solution outline
- Glycolysis:
- Net ATP from substrate-level phosphorylation: 2 ATP
- Reduced coenzymes: 2 reduced NAD
- Link Reaction (x2 for one glucose):
- Reduced coenzymes: 2 reduced NAD
- Krebs Cycle (x2 for one glucose):
- ATP from substrate-level phosphorylation: 2 ATP
- Reduced coenzymes: 6 reduced NAD + 2 reduced FAD
- Total reduced coenzymes for Oxidative Phosphorylation:
- Total reduced NAD = 2 (glycolysis) + 2 (link) + 6 (Krebs) = 10 reduced NAD
- Total reduced FAD = 2 reduced FAD (from Krebs)
- ATP from Oxidative Phosphorylation:
- From 10 reduced NAD: $10 \times 2.5 = 25
- From 2 reduced FAD: $2 \times 1.5 = 3
- Total from oxidative phosphorylation = $25 + 3 = 28
- Total ATP Yield:
- Sum of ATP from all stages = ATP (substrate-level) + ATP (oxidative phosphorylation)
- Total = (2 ATP from glycolysis + 2 ATP from Krebs) + 28 ATP
- Final Answer: 32 ATP