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9700 · 13.2

Investigation of limiting factors — practice questions

Practice and worked examples for 9700 Investigation of limiting factors. Short previews only — attempt the full question in MarkScheme against the official scheme.

Worked example 1

An experiment was set up to investigate the effect of light intensity and carbon dioxide concentration on the rate of photosynthesis in Elodea. The rate of photosynthesis was measured by counting the number of oxygen bubbles produced per minute. The results are shown in the graph below.

[A graph shows Rate of O₂ production vs. Light intensity. Two curves are plotted: 'High CO₂' and 'Low CO₂'. Both start at the origin. The 'Low CO₂' curve increases and then plateaus at a lower rate. The 'High CO₂' curve increases more steeply and plateaus at a much higher rate.]

With reference to the graph:

(a) Describe the effect of increasing light intensity on the rate of photosynthesis at low carbon dioxide concentration. (b) Explain why the rate of photosynthesis at high carbon dioxide concentration is higher than at low carbon dioxide concentration, especially at high light intensities. (c) Identify the limiting factor(s) in the region where the graph for 'High CO₂' concentration plateaus. Justify your answer.

Show solution outline

(a) Description: At low carbon dioxide concentration, as light intensity increases from zero, the rate of photosynthesis initially increases proportionally. However, the rate levels off (plateaus) at a relatively low light intensity. Beyond this point, further increases in light intensity do not cause an increase in the rate of photosynthesis.

(b) Explanation: At high light intensities, light is no longer the limiting factor. Carbon dioxide is required for the light-independent reactions (Calvin cycle) as a substrate for the enzyme RuBisCO. With a high CO₂ concentration, there is more substrate available for RuBisCO to fix. This allows the Calvin cycle to proceed more rapidly, regenerating ADP and NADP for the light-dependent reactions faster, leading to a higher overall rate of photosynthesis compared to when CO₂ is scarce.

(c) Identifying Limiting Factor at Plateau: In the region where the 'High CO₂' curve plateaus, the limiting factor is no longer light intensity (as increasing it has no effect) or carbon dioxide concentration (as it is supplied at a high level). The limiting factor is likely to be temperature or another factor related to the plant itself, such as the concentration of photosynthetic enzymes (e.g., RuBisCO) or the number of chloroplasts. This is because the rate has reached a maximum, indicating that some other component of the photosynthetic machinery is operating at its maximum capacity.

Worked example 2

An experiment was conducted to investigate the effect of light on the rate of the light-dependent stage of photosynthesis using DCPIP. Isolated chloroplasts were suspended in a buffered solution with DCPIP and exposed to a high, constant light intensity. The absorbance of the solution was measured at 600 nm every 30 seconds using a colorimeter. The results are shown in the table.

Time (s)Absorbance at 600 nm
00.80
------
300.65
600.50
900.35
1200.20
1500.10
1800.10

(a) Calculate the initial rate of reaction in absorbance units per second. (b) Explain why the absorbance stops decreasing after 150 seconds.

Show solution outline

(a) Calculating the Initial Rate: The initial rate of reaction is the gradient of the initial, linear portion of the curve when absorbance is plotted against time. We can calculate this from the table.

Step 1: Identify the linear portion. The absorbance decreases steadily from t=0 s to t=120 s. We can use points from this section to calculate the gradient.

Step 2: Choose two points to calculate the gradient (change in y / change in x). Let's use the points (0 s, 0.80) and (120 s, 0.20).

Change in Absorbance (Δy) = 0.20 - 0.80 = -0.60 Change in Time (Δx) = 120 s - 0 s = 120 s

Step 3: Calculate the rate. Rate = Δy / Δx = -0.60 / 120 s = -0.005 absorbance units s⁻¹

Since rate is typically expressed as a positive value, we can state the rate of decrease is 0.005 absorbance units s⁻¹.

Final Answer: The initial rate of reaction is 0.005 absorbance units s⁻¹.

(b) Explanation for Plateau: The absorbance stops decreasing after 150 seconds because the reaction has stopped. This indicates that one of the reactants has been completely used up and has become the limiting factor. Since light intensity is high and constant, and chloroplasts are present, the most likely limiting factor is the DCPIP. All the available DCPIP has been reduced, so it has turned from blue to colourless, and no further change in absorbance can occur.