9701 · 23.1
Lattice energy and Born-Haber cycles — FAQ
Frequently asked questions for 9701 Lattice energy and Born-Haber cycles. Direct answers first, then deeper explanation — then practise with marking.
What is the difference between lattice energy and lattice dissociation enthalpy?
They are the reverse of each other. Lattice energy (as defined by Cambridge International) is the enthalpy change when 1 mole of solid is formed from its gaseous ions (exothermic, negative value). Lattice dissociation enthalpy is the enthalpy change to break 1 mole of solid into its gaseous ions (endothermic, positive value). They have the same magnitude but opposite signs.
Why is the second electron affinity (e.g., for oxygen) an endothermic process?
The first electron affinity (O(g) + e⁻ → O⁻(g)) is exothermic. However, to form the O²⁻ ion, you must add a second electron to the already negative O⁻ ion (O⁻(g) + e⁻ → O²⁻(g)). There is strong electrostatic repulsion between the negative electron and the negative ion, so energy must be supplied to force the electron on. This makes the process endothermic.
Can you use a Born-Haber cycle for a covalent compound like methane, CH₄?
No, you cannot. The concept of a Born-Haber cycle is fundamentally based on the formation of an ionic lattice from gaseous ions. Covalent compounds like methane consist of discrete molecules held together by weak intermolecular forces in the solid state, not a lattice of ions. The energy terms, such as lattice energy and electron affinity, are not applicable in the same way.
Why do we have to use an indirect route like the Born-Haber cycle to find lattice energy?
It is practically impossible to perform an experiment that directly measures the process of gaseous ions coming together to form a solid lattice. We cannot easily create a gas of just cations and anions and measure the heat released as they combine. The Born-Haber cycle is a clever application of Hess's Law that allows us to calculate this value using other enthalpy changes that can be measured experimentally.