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9701 · 28.5

Stability constants, Kstab flashcards

Revision flashcards for Cambridge 9701 Stability constants, Kstab (syllabus 28.5). Flip, recall, then mark a real past-paper question.

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    What is the stability constant, Kstab?

    Kstab is the equilibrium constant for the formation of a complex ion in a solvent from its constituent metal ion and ligands.

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    Write the general expression for Kstab.

    For the equilibrium M(aq) + nL(aq) ⇌ [MLn](aq), the stability constant is Kstab = [[MLn]] / ([M][L]ⁿ).

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    What does a large value of Kstab indicate?

    A large Kstab (e.g., > 10⁴) indicates that the complex ion is very stable and the equilibrium lies far to the right, favouring the products.

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    How are the units of Kstab determined?

    The units depend on the stoichiometry of the formation equation. They are calculated by substituting and cancelling the units of concentration (mol dm⁻³) in the Kstab expression.

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    What is a stepwise stability constant?

    It is the equilibrium constant for the addition of a single ligand to a metal ion or a complex ion that already contains ligands. For example, K₁ is for M + L ⇌ ML.

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    What is the relationship between the overall stability constant (βn) and stepwise constants (K₁, K₂, etc.)?

    The overall stability constant is the product of the individual stepwise stability constants. βn = K₁ × K₂ × K₃ × ... × Kn.

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    How can Kstab values be used to predict the outcome of a ligand substitution reaction?

    The ligand that forms the complex with the significantly larger Kstab value will displace the other ligand(s). The equilibrium favours the formation of the more stable complex.

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    What is the chelate effect?

    The observation that complexes formed by polydentate ligands (chelating agents) are significantly more stable than those formed by a comparable number of monodentate ligands. This is due to a large, favourable entropy change.

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    Why is the Kstab for [Cu(EDTA)]²⁻ much larger than for [Cu(NH₃)₄]²⁺?

    EDTA⁴⁻ is a hexadentate ligand, so its complex benefits from the chelate effect, resulting in a large positive entropy change and thus a much higher stability constant compared to the complex with the monodentate ligand NH₃.

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    A common exam trap: What is the difference between Kstab and Kc?

    Kstab is a specific type of Kc. While both are equilibrium constants, Kstab specifically refers to the equilibrium for the formation of a complex ion from its components in solution.