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9701 · 29.1

Formulas, functional groups and the naming of organic compounds — practice questions

Practice and worked examples for 9701 Formulas, functional groups and the naming of organic compounds. Short previews only — attempt the full question in MarkScheme against the official scheme.

Worked example 1

Give the systematic IUPAC name for the following compound: CH₃CH(CH₃)CH₂COOH

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  1. Principal Functional Group: The –COOH group is a carboxylic acid, so the suffix is '-oic acid'.
  2. Longest Chain: The longest chain containing the –COOH group has 4 carbon atoms (but-). The carbon in the COOH group is always C1.
  3. Numbering: The chain is numbered starting from the carboxylic acid carbon as C1. So, C1 is the COOH carbon, C2 is CH₂, C3 is CH(CH₃), and C4 is CH₃.
  4. Substituents: There is a methyl group (–CH₃) on carbon 3.
  5. Assemble Name: The substituent is '3-methyl'. The parent chain is 'butan-'. The suffix is '-oic acid'. Combining these gives 3-methylbutanoic acid.

Worked example 2

Draw the skeletal formula for 3-methylpentan-2-ol and classify it as primary, secondary, or tertiary.

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  1. Name analysis: 'pentan-' means a 5-carbon chain. '-2-ol' means an –OH group is on carbon 2. '3-methyl' means a –CH₃ group is on carbon 3.
  2. Structure: The chain is C-C-C-C-C. Numbering from the right, the –OH is on C2 and the –CH₃ is on C3. The structural formula is CH₃CH₂CH(CH₃)CH(OH)CH₃.
  3. Skeletal Formula: Draw a zig-zag line with 5 points (for 5 carbons). From the second carbon, draw a line for the –OH group. From the third carbon, draw a line for the –CH₃ group.

Skeletal Formula\text{Skeletal Formula}

(A zig-zag line of 4 strokes representing the 5-carbon chain. A vertical line upwards from the 3rd carbon point. A line with 'OH' at the end coming off the 2nd carbon point.) 4. Classification: The carbon atom bonded to the –OH group (C2) is itself bonded to two other carbon atoms (C1 and C3). Therefore, it is a secondary (2°) alcohol.