Worked example 1
Draw a dot-and-cross diagram to show the bonding in magnesium chloride, MgCl₂.
Show solution outline
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Identify valence electrons: Magnesium (Group 2) has 2 valence electrons. Chlorine (Group 17) has 7 valence electrons.
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Determine ion formation: Mg loses 2 electrons to form Mg²⁺. Each Cl atom gains 1 electron to form Cl⁻. To balance the charges, one Mg atom reacts with two Cl atoms.
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Draw the diagram:
- Draw the magnesium ion: Show the Mg symbol in the centre. Place it in square brackets with a 2+ charge. The outer shell is now the one below the original valence shell, which is full (but we often don't draw the electrons for the cation, just the symbol and charge, as the shell is now empty). Syllabus convention is to show an empty outer shell.
- Draw the chloride ions: Draw two Cl ions. For each, show the original 7 electrons (e.g., as crosses) and the 1 electron gained from magnesium (e.g., as a dot). This makes 8 electrons in the outer shell. Place each ion in square brackets with a -1 charge.
Final Diagram: One [Mg]²⁺ ion shown alongside two [Cl]⁻ ions. Each chloride ion's bracket should contain the 'Cl' symbol and 8 outer electrons (e.g., 7 crosses and 1 dot).