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9231 · 1.5

Polar coordinates — common mistakes

Common exam mistakes on 9231 Polar coordinates. Learn what loses marks, then practise the topic with Examiner’s Ink.

Exam tip 1

Always draw a sketch before calculating an area. This helps you identify the correct limits of integration and any symmetries. Forgetting the 12\frac{1}{2} in the area formula is a very common mistake. Also, be prepared to use double angle identities like cos(2θ)=2cos2θ1=12sin2θ\cos(2\theta) = 2\cos^2\theta - 1 = 1 - 2\sin^2\theta to integrate terms like cos2θ\cos^2\theta or sin2θ\sin^2\theta.

What happens if $r$ is negative?

If rr is negative for a certain angle θ\theta, you plot the point at a distance of r|r| from the pole, but in the direction exactly opposite to θ\theta. This means you plot it along the line defined by the angle θ+π\theta + \pi. For example, the point (2,π/4)(-2, \pi/4) is plotted at the same location as (2,5π/4)(2, 5\pi/4).

How do I choose the limits of integration for an area calculation?

The limits, α\alpha and β\beta, are the starting and ending angles that trace out the boundary of the desired region. A sketch is vital. For a single closed loop that passes through the pole, the limits are often two consecutive values of θ\theta for which r=0r=0. For symmetrical shapes, you can calculate the area of a smaller part and multiply.

Why is the area formula $\frac{1}{2}\int r^2 d\theta$ and not something simpler?

This formula comes from summing the areas of tiny sectors, not rectangles. The area of a circular sector with radius rr and angle Δθ\Delta\theta (in radians) is 12r2Δθ\frac{1}{2}r^2 \Delta\theta. When we make the angle infinitesimally small (dθd\theta), we can integrate this expression to find the total area swept out by the radius as it rotates.

Can a point have multiple polar coordinates?

Yes, unlike Cartesian coordinates, polar coordinates are not unique. Adding any multiple of 2π2\pi to θ\theta gives the same point. For example, (r,θ)(r, \theta) is the same point as (r,θ+2π)(r, \theta + 2\pi) and (r,θ2π)(r, \theta - 2\pi). Also, as mentioned, (r,θ)(r, \theta) is the same as (r,θ+π)(-r, \theta + \pi).