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9709 · 1.8

Integration — common mistakes

Common exam mistakes on 9709 Integration. Learn what loses marks, then practise the topic with Examiner’s Ink.

Exam tip 1

If a question asks for the 'total area' of a region that is partly above and partly below the x-axis, you must calculate two separate definite integrals. Find the x-intercept where the curve crosses the axis, split the integral at that point, and add the absolute values of the two results. A single integral across the whole region will give the 'net area', which might be incorrect.

What is the difference between an indefinite and a definite integral?

An indefinite integral, f(x)dx\int f(x) \, dx, gives a function, F(x)+CF(x) + C, representing a family of curves. A definite integral, abf(x)dx\int_a^b f(x) \, dx, gives a single numerical value, representing the net area under the curve between x=ax=a and x=bx=b.

What if the function is below the x-axis?

If the curve y=f(x)y=f(x) is below the x-axis between x=ax=a and x=bx=b, the definite integral abf(x)dx\int_a^b f(x) \, dx will be negative. The geometric area is the absolute value (the positive magnitude) of this result.

Why can't we integrate $1/x$ using the power rule?

The power rule for xnx^n is xn+1n+1+C\frac{x^{n+1}}{n+1} + C. For 1/x=x11/x = x^{-1}, we have n=1n=-1. Applying the rule would lead to division by n+1=1+1=0n+1 = -1+1 = 0, which is undefined. The integral of 1/x1/x is a different function, lnx\ln|x|, which is covered in the A2 syllabus (Paper 3).

How do I find the area between two curves?

To find the area between two curves, y=f(x)y=f(x) and y=g(x)y=g(x), from x=ax=a to x=bx=b, where f(x)f(x) is the upper curve, you calculate the integral of the difference: Area =ab(f(x)g(x))dx= \int_a^b (f(x) - g(x)) \, dx. The limits aa and bb are often the x-coordinates of the points where the curves intersect.