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9709 · 2.1

Algebra — common mistakes

Common exam mistakes on 9709 Algebra. Learn what loses marks, then practise the topic with Examiner’s Ink.

Exam tip 1

When finding the constants (A, B, C...), substituting strategic values of xx is often much faster than equating coefficients. For a term Axa\frac{A}{x-a}, substituting x=ax=a into the cross-multiplied equation will quickly isolate AA. Also, always check if the fraction is improper (degree of numerator \ge degree of denominator) before you start. If it is, you must perform polynomial division first.

Exam tip 2

A very common question asks for the expansion and the range of values for which it is valid. Do not forget to state the validity range, e.g., x<12|x| < \frac{1}{2}. This is an easy mark to gain and an easy one to lose. Be careful with signs, especially when nn is negative.

When solving $|f(x)| = |g(x)|$, is squaring both sides always the best method?

Squaring is a very reliable method because it correctly removes the modulus signs. However, it can lead to a more complicated polynomial to solve. The alternative method, setting f(x)=g(x)f(x) = g(x) and f(x)=g(x)f(x) = -g(x), can be quicker but requires careful management of signs and brackets. Both methods are valid; choose the one you are most comfortable and accurate with.

What's the difference between the Remainder Theorem and the Factor Theorem?

The Factor Theorem is simply a special case of the Remainder Theorem. The Remainder Theorem tells you the remainder when you divide a polynomial P(x)P(x) by (xa)(x-a) is P(a)P(a). The Factor Theorem states that if this remainder P(a)P(a) happens to be 0, then (xa)(x-a) must be a factor.

Why do we learn partial fractions? What are they used for?

The primary application of partial fractions in A-Level Mathematics is in integration (which you will study in depth). It is much easier to integrate a sum of simple fractions (like 2x1+3x+2\frac{2}{x-1} + \frac{3}{x+2}) than it is to integrate the single complex fraction they came from. We also use them in binomial expansions.

For the binomial expansion, what if the power is a positive integer?

If the power nn is a positive integer, the expansion formula still works, but it will terminate. The term with (nn)(n-n) in the numerator will become zero, so all subsequent terms are zero. This gives a finite series, the same as the one you learned in P1 using combinations (nCr).