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9709 · 2.2

Logarithmic and exponential functions — common mistakes

Common exam mistakes on 9709 Logarithmic and exponential functions. Learn what loses marks, then practise the topic with Examiner’s Ink.

Exam tip 1

Your calculator's ln button is for the natural logarithm (loge\log_e). The log button is usually for base 10 (log10\log_{10}). For solving equations, it's often best to use ln as it simplifies expressions involving ee. Remember the key inverse properties: ln(ex)=x\ln(e^x) = x and elnx=xe^{\ln x} = x (for x>0x>0).

Exam tip 2

When solving logarithmic equations, always check your final answers by substituting them back into the original equation. This is to ensure that you are not taking the logarithm of a negative number or zero, which is undefined. Any solution that violates this condition must be rejected.

Why can't I take the log of a negative number?

A logarithm, logax\log_a x, asks 'what power must I raise aa to, to get xx?' If the base aa is positive, raising it to any real power will always result in a positive number. For example, 23=82^3=8, 23=1/82^{-3}=1/8, 20=12^0=1. There is no real power you can raise 2 to that will give a negative result. Therefore, the argument of a logarithm must be positive.

What's the difference between `log` and `ln` on my calculator?

Typically, the log button refers to the common logarithm, which has a base of 10 (i.e., log10x\log_{10}x). The ln button refers to the natural logarithm, which has a base of ee (i.e., logex\log_e x). For solving equations like ax=ba^x=b, you can use either base, and the change of base formula guarantees you will get the same answer.

How do I remember the laws of logarithms?

The laws of logarithms directly mirror the laws of indices. Think about the connection:

  • Multiplication of numbers becomes addition of their powers (am×an=am+na^m \times a^n = a^{m+n}), which corresponds to the log rule log(xy)=logx+logy\log(xy) = \log x + \log y.
  • Division of numbers becomes subtraction of their powers (am/an=amna^m / a^n = a^{m-n}), which corresponds to log(x/y)=logxlogy\log(x/y) = \log x - \log y.