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9709 · 6.5

Hypothesis tests — FAQ

Frequently asked questions for 9709 Hypothesis tests. Direct answers first, then deeper explanation — then practise with marking.

What's the difference between a p-value and a significance level (alpha)?

The significance level, α\alpha, is a threshold you set before you conduct the test. It's your standard for how strong the evidence needs to be. The p-value is calculated from your data. It's the probability of seeing your sample result (or something more extreme) if the null hypothesis were true. You reject H0H_0 if your p-value is smaller than your chosen α\alpha.

Why do we divide alpha by 2 for a two-tailed test?

In a two-tailed test, an 'extreme' result could be either significantly higher or significantly lower than the null hypothesis value. The significance level α\alpha represents the total probability of making a Type I error. We split this probability between the two possible extremes (the two tails of the distribution), so each tail has a probability of α/2\alpha/2.

What happens if my test statistic is exactly equal to the critical value?

This is a very rare occurrence in practice. By convention, if the test statistic is in the critical region (e.g., for Z1.645Z \le -1.645, if Z=1.645Z = -1.645), you reject H0H_0. However, it highlights that the boundary is arbitrary. In an exam, you should state your comparison clearly (e.g., 1.645=1.645-1.645 = -1.645) and follow the rule to reject H0H_0.

Do I need to use a continuity correction for hypothesis tests on proportions?

In the 9709 syllabus, continuity corrections are required when approximating a discrete distribution (like Binomial or Poisson) with a continuous one (Normal), especially for finding probabilities of specific ranges. For hypothesis testing of a proportion, where you are testing a single sample proportion p^\hat{p}, a continuity correction is generally not required or expected. The Normal approximation to the sampling distribution of p^\hat{p} is considered adequate without it, provided np>5np > 5 and n(1p)>5n(1-p) > 5.