Worked example 1
The period T of a simple pendulum is thought to depend on its length l and the acceleration of free fall g. The proposed equation is T = 2π√(l/g). Use dimensional analysis to show that this equation is homogeneous.
Show solution outline
- Identify the base units for each side of the equation.
- LHS (Left Hand Side): The quantity is period T, which is a time. Its SI base unit is seconds (s).
- RHS (Right Hand Side): The equation involves length l (unit: m) and acceleration g (unit: m s⁻²). The term 2π is a dimensionless constant and has no units.
- Analyse the units of the LHS.
- [LHS] = [T] = s
- Analyse the units of the RHS.
- [RHS] = [√(l/g)]
- Substitute the units: [RHS] = √(m / (m s⁻²))
- Simplify the units on the RHS.
- [RHS] = √(m × s² / m)
- The 'm' units cancel out: [RHS] = √(s²)
- [RHS] = s
- Compare LHS and RHS.
- [LHS] = s and [RHS] = s.
- Since the base units on both sides are identical, the equation is dimensionally homogeneous.