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9702 · 13.1

Gravitational field flashcards

Revision flashcards for Cambridge 9702 Gravitational field (syllabus 13.1). Flip, recall, then mark a real past-paper question.

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    How is gravitational field strength (g) defined?

    The gravitational force acting per unit mass at a given point.

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    What two factors does Newton's Law of Gravitation state the attractive force depends on?

    Directly proportional to the product of the masses; inversely proportional to the square of the distance between their centres.

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    Why is gravitational potential considered negative?

    Because work is done *by* the field (energy is released) when a mass moves from infinity (where potential is zero) into the field.

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    What do closer gravitational field lines indicate about the field?

    They indicate a stronger gravitational field in that region.

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    For calculations involving objects *outside* a uniform sphere, how can its mass be considered?

    As if it's concentrated entirely at its centre, acting as a point mass.

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    What is the universal gravitational constant G?

    A fundamental constant ($6.67 \times 10^{-11} \text{ N m}^2 \text{ kg}^{-2}$) that quantifies the strength of the gravitational force.

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    What does gravitational field strength (g) also represent?

    The acceleration an object would experience if allowed to fall freely in that field.

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    What is gravitational potential ($\phi$)?

    The work done per unit mass to bring a unit mass from infinity to a specific point in the field.

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    What is the conventional value for gravitational potential at an infinite distance from a mass?

    Zero.

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    How does gravitational field strength vary with distance in a radial field?

    It follows an inverse square law (g \propto 1/r^2).

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    What is the formula for gravitational potential ($\phi$) at a distance r from a mass M?

    $\phi = -\frac{GM}{r}$

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    How does the graph of gravitational field strength (g) against distance (r) from a point mass look?

    It's a curve in the first quadrant, starting high and decreasing rapidly towards zero, following an inverse square law ($g \propto 1/r^2$). It is always positive.

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    How does the graph of gravitational potential ($\phi$) against distance (r) look?

    It's a curve in the fourth quadrant (negative values), starting at its most negative value and increasing towards zero as r increases, following an inverse law ($\phi \propto -1/r$).

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    What is the relationship between gravitational field strength (g) and the gradient of the gravitational potential ($\phi$) graph?

    The field strength is the negative of the potential gradient: $g = -\frac{d\phi}{dr}$.