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9702 · 2.1

Equations of motion flashcards

Revision flashcards for Cambridge 9702 Equations of motion (syllabus 2.1). Flip, recall, then mark a real past-paper question.

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    What does uniform acceleration mean?

    The velocity of an object changes at a constant rate.

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    State one of the SUVAT equations that does not involve final velocity ($v$).

    $s = ut + \frac{1}{2}at^2$

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    What information does the area under a velocity-time graph provide?

    The total displacement of the object.

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    What is the typical initial velocity ($u$) for an object dropped from rest?

    $0 \, \text{m/s}$

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    How are horizontal and vertical components of motion treated in projectile problems?

    They are analyzed independently of each other.

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    Define displacement ($s$).

    The overall change in position from a starting point, including direction (a vector quantity).

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    What does the gradient of a displacement-time graph represent?

    The object's velocity.

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    What is the approximate value and direction of acceleration due to gravity ($g$)?

    $9.81 \, \text{m/s}^2$ in a downwards direction.

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    Is velocity a scalar or vector quantity?

    Velocity is a vector quantity (it has both magnitude and direction).

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    Which SUVAT equation would you use if time ($t$) is not known or required?

    $v^2 = u^2 + 2as$

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    What happens to the horizontal velocity of a projectile (ignoring air resistance)?

    It remains constant throughout the motion.

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    What is the acceleration of a projectile at the peak of its trajectory?

    The acceleration is constant throughout the flight and is equal to the acceleration due to gravity, g (9.81 m/s² downwards), even at the peak where vertical velocity is momentarily zero.

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    What is the vertical velocity of a projectile at its maximum height?

    0 m/s. The projectile momentarily stops moving upwards before it begins to fall back down.

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    What physical quantity is represented by the area under an acceleration-time graph?

    The change in velocity (Δv).

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    How do you resolve an initial velocity 'u' at an angle 'θ' to the horizontal into its components?

    Horizontal component: uₓ = u cos(θ). Vertical component: uᵧ = u sin(θ).