9702 · 22.2
Photoelectric effect — FAQ
Frequently asked questions for 9702 Photoelectric effect. Direct answers first, then deeper explanation — then practise with marking.
Why does the photoelectric effect only happen above a certain frequency?
Because electrons need a minimum amount of energy (the work function, Φ) to escape the metal. Since photon energy E = hf, only photons with a frequency equal to or greater than the threshold frequency (f₀) will have enough individual energy to eject an electron. Below f₀, photons simply don't have enough energy, regardless of how many there are.
What is the difference between work function and threshold frequency?
The work function (Φ) is the minimum energy an electron needs to absorb to escape the metal surface, measured in Joules or electronvolts. The threshold frequency (f₀) is the minimum frequency of incident light required for photons to provide this specific energy, related by the equation Φ = hf₀.
How does increasing light intensity affect the number of emitted electrons?
Above the threshold frequency, increasing the intensity of light means more photons are striking the metal surface per second. Since each photon can potentially eject one electron, a higher intensity leads to a greater number of electrons being emitted per second, resulting in a larger photocurrent.
What is stopping potential and how does it relate to kinetic energy?
Stopping potential (V_s) is the reverse voltage needed to stop the fastest photoelectrons. The work done by this potential (eV_s) must equal the maximum kinetic energy of the electrons. Therefore, KE_max = eV_s. This provides a direct experimental method for measuring the maximum kinetic energy.