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9702 · 8.4

The diffraction grating — common mistakes

Common exam mistakes on 9702 The diffraction grating. Learn what loses marks, then practise the topic with Examiner’s Ink.

Exam tip 1

Always remember to convert all units to SI (metres for dd and λ\lambda) before applying the formula. The grating spacing dd is the reciprocal of the number of lines per metre. Pay close attention to the number of lines per millimetre, as this requires a calculation to find dd. Also, clearly state the value of 'n' you are using, especially when calculating the maximum possible order, which must be an integer.

How does a diffraction grating differ from a prism in splitting light?

Both split white light into a spectrum. However, a prism does this through dispersion (different refractive indices for different wavelengths), while a diffraction grating does so via diffraction and interference. Gratings generally produce a much wider, more distinct, and more angularly separated spectrum, with angles depending on wavelength and grating spacing, not the prism material's refractive index.

Why is coherent light essential for observing interference patterns from a grating?

Coherent light ensures that the waves passing through different slits maintain a constant phase relationship and have the same frequency. Without coherence, the phase differences at any point on the screen would fluctuate randomly, leading to rapidly changing interference conditions. This would result in an unstable and unobservable pattern, or merely a general blurring of light, not distinct bright and dark fringes.

What determines the maximum number of orders observable from a diffraction grating?

The maximum number of orders (nmaxn_{max}) is limited by the physical constraint that sinθcannotexceed1\sin \theta cannot exceed 1. Therefore, for any order nn where the ratio nλ/dn\lambda/d is greater than 1, no real angle θexistsforthatmaximum\theta exists for that maximum, and it will not be observed. You can find nmaxn_{max} by setting sinθ=1inthegratingequationandsolvingfor\sin \theta = 1 in the grating equation and solving for n$$, then taking the integer part of the result.

Can the different orders of spectra from a grating overlap?

Yes, they can, especially at higher orders. For example, the third-order maximum for a shorter wavelength (like violet) might appear at the same angle as the second-order maximum for a longer wavelength (like red). This can be checked using the condition n₁λ₁ = n₂λ₂. This overlapping is a key difference from the single, non-overlapping spectrum produced by a prism.