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9700 · 1.2

Cells as the basic units of living organisms — practice questions

Practice and worked examples for 9700 Cells as the basic units of living organisms. Short previews only — attempt the full question in MarkScheme against the official scheme.

Worked example 1

A scientist observes two different cells, Cell A and Cell B, under a microscope. Their key features are recorded in the table below.

FeatureCell ACell B
NucleusAbsentPresent
---------
RibosomesPresentPresent
MitochondriaAbsentPresent
Cell wallPresent (peptidoglycan)Present (cellulose)
DNA arrangementCircular chromosome in nucleoidLinear chromosomes in nucleus
  1. Identify whether Cell A is a prokaryotic cell or a eukaryotic cell. Justify your answer using two features from the table.
  2. Identify whether Cell B is a prokaryotic cell or a eukaryotic cell. Justify your answer using two features from the table.
Show solution outline
  1. Cell A is a prokaryotic cell.
    • Justification 1: It lacks a true nucleus. Prokaryotic cells do not have their genetic material enclosed within a nuclear membrane.
    • Justification 2: It has a cell wall made of peptidoglycan. This is characteristic of bacterial (prokaryotic) cell walls, distinct from eukaryotic plant or fungal cell walls. (Other valid justifications include: absence of mitochondria, circular DNA in nucleoid).
  2. Cell B is a eukaryotic cell. (Specifically, a plant cell due to the cellulose cell wall).
    • Justification 1: It possesses a true nucleus. Eukaryotic cells have their genetic material (DNA) enclosed within a double membrane, forming a nucleus.
    • Justification 2: It has mitochondria. These are membrane-bound organelles found in eukaryotic cells for aerobic respiration. (Other valid justifications include: cell wall made of cellulose, linear chromosomes in nucleus).

Worked example 2

An electron micrograph shows a mitochondrion with a measured length of 4.5 cm. The magnification of the micrograph is stated as ×90,000. Calculate the actual length of the mitochondrion in micrometres (μm).

Show solution outline

Step 1: State the magnification formula Magnification (M) = Image size (I) / Actual size (A)

Step 2: Rearrange the formula to find the Actual size (A) Actual size (A) = Image size (I) / Magnification (M)

Step 3: Ensure units are consistent before calculating The image size is in cm, but the final answer needs to be in μm. It's best to convert the image size to a smaller unit like millimetres (mm) first. Image size (I) = 4.5 cm = 45 mm

Step 4: Substitute the values into the rearranged formula Actual size (A) = 45 mm / 90,000

Step 5: Calculate the actual size in mm Actual size (A) = 0.0005 mm

Step 6: Convert the actual size from mm to micrometres (μm) We know that 1 mm = 1000 μm. Actual size (A) = 0.0005 mm × 1000 = 0.5 μm

Final Answer: The actual length of the mitochondrion is 0.5 μm.