9700 · 2.1
Testing for biological molecules — FAQ
Frequently asked questions for 9700 Testing for biological molecules. Direct answers first, then deeper explanation — then practise with marking.
Why is heating important for the Benedict's test in 9700 Biology?
Heating provides the activation energy for the redox reaction to occur between the reducing sugar and the copper(II) ions in Benedict's solution. Without sufficient heat (ideally from a water bath at >80°C), the characteristic colour change and brick-red precipitate indicating the presence of reducing sugars will not form, or will form very slowly. To master this and other key concepts, explore our free 9700 Biology course and practice with past papers.
What's the difference between testing for reducing and non-reducing sugars?
The key difference is the pre-treatment for non-reducing sugars. Reducing sugars react directly with Benedict's solution upon heating. Non-reducing sugars, like sucrose, first need to be hydrolysed (broken down) into their constituent reducing monosaccharides using dilute acid and heat, followed by neutralisation with alkali, before the Benedict's test can be performed to show a positive result. This crucial distinction is often tested in Cambridge 9700 exams. Our free resources, including past papers, can help clarify this.
How do I avoid common errors in biological molecule tests for 9700?
Focus on precision. Always state both initial and final colours, and differentiate between a solution, precipitate, and emulsion. Ensure correct temperatures (e.g., heating for Benedict's, room temperature for iodine). For non-reducing sugars, don't forget the neutralisation step. For the emulsion test, use a dry test tube initially. Practise writing out the full procedure and expected results, paying attention to detail. Our free revision lessons and extensive collection of past papers are designed to help you hone these skills for Cambridge 9700 Biology.