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9709 · 5.5

The normal distribution — FAQ

Frequently asked questions for 9709 The normal distribution. Direct answers first, then deeper explanation — then practise with marking.

Why is the variance $\sigma^2$ used in the notation $N(\mu, \sigma^2)$ instead of the standard deviation $\sigma$?

This is a mathematical convention. Variance has useful additive properties that standard deviation does not. For example, the sum of two independent normal variables has a variance that is the sum of their variances. Using variance in the notation makes these theoretical properties clearer.

What do I do if my calculated z-value is not in the table?

The standard normal table in the Cambridge formula book (MF19/MF20) is quite comprehensive. If a value is between two listed values, you can perform linear interpolation to get a more accurate probability. For values larger than those in the main table (e.g., z > 3.5), the probability P(Z<z)P(Z < z) is very close to 1.

How do I know when to use a continuity correction?

You must use a continuity correction whenever you are using a continuous distribution (like the normal distribution) to approximate a discrete distribution (like the binomial or Poisson distributions). If the original problem involves a variable that can only take integer values, a continuity correction is required for the approximation.

Can I use the normal approximation for a Poisson distribution?

Yes. A Poisson distribution Po(λ)Po(\lambda) can be approximated by a normal distribution N(λ,λ)N(\lambda, \lambda) provided that λ\lambda is large (typically λ>15\lambda > 15). Just like with the binomial approximation, you must use a continuity correction.

What's the difference between $P(X < 5)$ and $P(X \le 5)$ for a normal distribution?

For any continuous distribution, including the normal distribution, the probability of the variable being exactly equal to a single value is zero. i.e., P(X=5)=0P(X=5)=0. Therefore, for a continuous variable XX, P(X<5)P(X < 5) is exactly the same as P(X5)P(X \le 5). This is NOT true for discrete distributions, which is why continuity corrections are so important when approximating.