9702 · 13.3
Gravitational field of a point mass
Cambridge 9702 Paper 4 — Gravitational field of a point mass (13.3). Senpai Corner diagram-backed pilot with premium structure and live visuals.
Need to know
What you need to know
- Force ($F$) is directly proportional to the product of masses ($m_1m_2$).
- Force ($F$) is inversely proportional to the square of the distance ($r^2$).
- $G$ is the universal gravitational constant ($6.67 \times 10^{-11} \text{ N m}^2 \text{kg}^{-2}$).
- The force is always attractive.
Explanation
Gravitational field of a point mass
- Force ($F$) is directly proportional to the product of masses ($m_1m_2$).
- Force ($F$) is inversely proportional to the square of the distance ($r^2$).
- $G$ is the universal gravitational constant ($6.67 \times 10^{-11} \text{ N m}^2 \text{kg}^{-2}$).
- The force is always attractive.