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9702 · 13.3

Gravitational field of a point mass

Cambridge 9702 Paper 4 — Gravitational field of a point mass (13.3). Senpai Corner diagram-backed pilot with premium structure and live visuals.

Need to know

What you need to know

  • Force ($F$) is directly proportional to the product of masses ($m_1m_2$).
  • Force ($F$) is inversely proportional to the square of the distance ($r^2$).
  • $G$ is the universal gravitational constant ($6.67 \times 10^{-11} \text{ N m}^2 \text{kg}^{-2}$).
  • The force is always attractive.

Explanation

Gravitational field of a point mass

  1. Force ($F$) is directly proportional to the product of masses ($m_1m_2$).
  2. Force ($F$) is inversely proportional to the square of the distance ($r^2$).
  3. $G$ is the universal gravitational constant ($6.67 \times 10^{-11} \text{ N m}^2 \text{kg}^{-2}$).
  4. The force is always attractive.